Generate multiple objects from a List

Question

I have a method that takes a variable argument list.

getSome(Object... numbers);

I have a List holding all the parameters that I want to pass to the method.

ArrayList<Long> numbersList;

How can I achieve the following for ALL number objects in the list?

getSome(numbersList.get(0), numbersList.get(1), ... numbersList.get(numbersList.size()-1));

How about `getSome(numbersList.toArray())` or `getSome(numbersList.toArray(new Long[numbersList.size()]))`? — Pshemo, Jul 23 '13 at 15:38
You should rewrite `getSome` to take a `List` then or add an overloaded method. why does your version take `Object...`? — Eric Jablow, Jul 23 '13 at 16:24

score 2 · Answer 1 · answered Jul 23 '13 at 15:37

2

You can transform your list into an array:

getSome(numbersList.toArray(new Long[numbersList.size()]));

answered Jul 23 '13 at 15:37

assylias

score 0 · Answer 2 · answered Jul 23 '13 at 15:37

0

Given the method declaration :

getSome(Object... numbers);

You can pass an array to it.

You can use the List#toArray() method to transform the List to an Long[]:

numbersList.toArray(new Long[numbersList.size()]);

answered Jul 23 '13 at 15:37

AllTooSir

2 Answers2