Null pointer exception in searchview

Question

I am trying to create list search view in shreyaloclistfragment. I am getting NullPointerException at folowing line

final SearchView searchView = (SearchView) menu.findItem(R.id.menu_search).getActionView();

My method is

@Override
public void onCreateOptionsMenu(Menu menu, MenuInflater inflater ) {
    super.onCreateOptionsMenu(menu, inflater);
    inflater.inflate( R.menu.menu_search, menu);
    System.out.println( "inflating menu");

    final SearchView searchView = (SearchView) menu.findItem(R.id.menu_search).getActionView();



    final SearchView.OnQueryTextListener queryTextListener = new SearchView.OnQueryTextListener() {
        @Override
        public boolean onQueryTextChange(String newText) {
            showFilteredItems( newText );
            return true;
        }

        @Override
        public boolean onQueryTextSubmit(String query) {
            return true;
        }
    };

    searchView.setOnQueryTextListener(queryTextListener);

    return;
}

Stack trace

FATAL EXCEPTION: main
java.lang.NullPointerException
at com.sears.syw.FragmentShopsTab.onCreateOptionsMenu(FragmentShopsTab.java:52)
at android.support.v4.app.Watson.onCreatePanelMenu(Watson.java:55)
at  


com.actionbarsherlock.ActionBarSherlock.callbackCreateOptionsMenu(ActionBarSherlock.java:559    )
at   

    com.actionbarsherlock.internal.ActionBarSherlockNative.dispatchCreateOptionsMenu(ActionBarSh    erlockNative.java:65)
at

Something is wrong with the inflation process such that an item with `R.id.menu_search` cannot be found. Wrong menu xml? — dmon, Jul 27 '13 at 20:55
nope...I am trying to replicate this (http://stackoverflow.com/questions/7230893/android-search-with-fragments) my eml file — Sanjeev Yadav, Jul 27 '13 at 20:59

score 9 · Answer 1 · answered Oct 16 '13 at 02:36

If you are using the Appcompat library, maybe you forgot to add your own xmlns on your menu_search.xml.

As the example says:

<menu xmlns:android="http://schemas.android.com/apk/res/android"
  xmlns:yourapp="http://schemas.android.com/apk/res-auto" >
<!-- Search, should appear as action button -->
<item android:id="@+id/action_search"
      android:icon="@drawable/ic_action_search"
      android:title="@string/action_search"
      yourapp:showAsAction="ifRoom"  />
</menu>

You need to add the folowing:

<item android:id="+@id/..."
      android:actionViewClass="android.widget.SearchView"
      yourapp:actionViewClass="android.widget.SearchView" />

Source: https://developer.android.com/training/basics/actionbar/adding-buttons.html#XML

score 4 · Answer 2 · edited Oct 04 '18 at 01:38

4

If you are using AppCompat library, then in your menu.xml, add

app:actionViewClass="android.support.v7.widget.SearchView"

instead of

app:actionViewClass="android.widget.SearchView"

edited Oct 04 '18 at 01:38

Pang

9,564
146
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answered Sep 29 '14 at 12:02

Shreyansh jain

76
2

Hi. Is there a Google document stating this fact? – Tejas Sherdiwala Jul 31 '15 at 01:19
Thanks a lot! Worked in my case :) – Jesper May 22 '17 at 17:51

score 3 · Answer 3 · answered Mar 03 '14 at 17:05

3

i am using android studio

<menu xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:app="http://schemas.android.com/apk/res-auto"
    xmlns:tools="http://schemas.android.com/tools"
    tools:context="com.app.myapp" >

    <item
        android:id="@+id/search"
        android:title="Buscar"
        android:icon="@drawable/ic_search"
        app:showAsAction="collapseActionView|ifRoom"
        android:actionViewClass="android.widget.SearchView"
        app:actionViewClass="android.widget.SearchView"/>

</menu>

found 100%

answered Mar 03 '14 at 17:05

Erick Guardado

59
2

Does that mean it's solved? Because I see in your XML the id is "search", but you are looking for "R.id.menu_search". Shouldn't that be "R.id.search"? – r0ber7 Mar 13 '14 at 15:34
no, android studio configure all in u android project, no is just the xml in the menu – Erick Guardado Apr 21 '14 at 17:46

score 0 · Answer 4 · answered Jul 27 '13 at 21:14

0

To reference a layout from a menu xml use the actionLayout attribute:

<menu>
<item android:id="@+id/menu_name"
  android:actionLayout="@layout/your_layout"
  android:showAsAction="always"/>
</menu>

answered Jul 27 '13 at 21:14

dmon

30,048
8
87
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Any idea how to create list search view in fragment? – Sanjeev Yadav Jul 27 '13 at 21:31
Now getting by implementing your changes java.lang.ClassCastException: android.widget.LinearLayout cannot be cast to android.widget.SearchView at com.sears.syw.FragmentShopsTab.onCreateOptionsMenu(FragmentShopsTab. java:52) at android.support.v4.app.Watson.onCreatePanelMenu(Watson.java:55) at com.actionbarsherlock.ActionBarSherlock.callbackCreateOptionsMenu(ActionBarSherlock.java:559) at – Sanjeev Yadav Jul 28 '13 at 05:04

score 0 · Answer 5 · answered May 09 '14 at 14:18

0

Some times problem is with

setHasOptionsMenu(true);

Move it from oncreate or onviewcreate to on attached method and try it.

answered May 09 '14 at 14:18

Swap-IOS-Android

4,363
6
49
77

score 0 · Answer 6 · edited May 23 '17 at 12:34

0

Check this answer Either you are using wrong namespace or importing wrong class https://stackoverflow.com/a/38702262/5374951

edited May 23 '17 at 12:34

Community

1
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answered Aug 01 '16 at 15:12

ketankk

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1
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Null pointer exception in searchview

6 Answers6