How to ignore a specific property when deserializing a JSON object?

Question

I am working against a existing REST interface. One of the incoming JSON objects contains a property called size which I would like to ignore when deserializing this JSON object?

My standard behavior is to fail on unknown property, so I cannot configure the used object mapper to ignore unknown properties.

Probably look at [this](http://stackoverflow.com/questions/11232045/serialization-and-deserialization-with-jackson-how-to-programmatically-ignore-f) ! — AllTooSir, Jul 29 '13 at 11:31

score 12 · Accepted Answer · edited Jul 30 '13 at 18:29

12

Add the annotation @JsonIgnoreProperties("size") to your POJO. See the JavaDoc for @JsonIgnoreProperties at fasterxml.github.io for more information.

edited Jul 30 '13 at 18:29

Oliver

3,815
8
35
63

answered Jul 29 '13 at 11:51

nutlike

4,835
1
25
33

11

Or, generally: @JsonIgnoreProperties(ignoreUnknown = true) – Michał Ziober Jul 29 '13 at 12:07
@MichałZiober: Since the question states "… I cannot configure the used object mapper to ignore unknown properties." I opted for the specific version, but you are certainly right. – nutlike Jul 29 '13 at 12:25
1

I know, but I wanted to show another possibility. Your answer is correct and should be used first. – Michał Ziober Jul 29 '13 at 12:31

score 0 · Answer 2 · answered Oct 04 '19 at 08:47

If the goal is to ignore property ONLY by deserialization, but still serialize it (read-only), it is possible with @JsonIgnoreProperties(value={ "size" }, allowGetters= true).

More info here: https://fasterxml.github.io/jackson-annotations/javadoc/2.6/com/fasterxml/jackson/annotation/JsonIgnoreProperties.html#allowGetters()

How to ignore a specific property when deserializing a JSON object?

2 Answers2