How to get list of URL-parameters from URL?
For example: http://example.com/blank.html?access_token=blablabla&expires_in=0&user_id=ablabl&secret=rararar.
I need to get access_token, expires_in, user_id, secret.
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Andrew Tsaryov
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1 Answers
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Use urlparse.parse_qs() or urlparse.parse_qsl() to parse the query string:
from urlparse import parse_qs, parse_qsl, urlparse
query_string = urlparse(url).query
if query_string:
data_as_dict = parse_qs(query_string) # returns a dictionary with lists
data_as_list = parse_qsl(query_string) # returns a list of tuples
Demo:
>>> from urlparse import parse_qs, parse_qsl
>>> url = 'http://example.com/blank.html?access_token=blablabla&expires_in=0&user_id=ablabl&secret=rararar'
>>> query_string = url.partition('?')[2]
>>> parse_qs(query_string)
{'access_token': ['blablabla'], 'user_id': ['ablabl'], 'secret': ['rararar'], 'expires_in': ['0']}
>>> parse_qsl(query_string)
[('access_token', 'blablabla'), ('expires_in', '0'), ('user_id', 'ablabl'), ('secret', 'rararar')]
Because any key in a query string can occur more than once, you can end up with more than one value per key. The parse_qs() function collects all values into lists per key, the parse_qsl() function simply returns each key-value pair as a tuple, letting you decide what to do with duplicates.
Martijn Pieters
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If you are using `urlparse`, isn't it better to use `urlparse.urlparse` or `urlparse.urlsplit` rather than `str.partition`? – Robᵩ Jul 29 '13 at 16:00
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@Robᵩ: It's a little overkill, in my experience. I find `str.partition()` just that little more.. handily available. – Martijn Pieters Jul 29 '13 at 16:01
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1But your example deals poorly with `#`, as in `http://example.com/?q1=a1&q2=a2#label`. – Robᵩ Jul 29 '13 at 16:10
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@Robᵩ: Touché, that *is* a good reason to not use partition. Will update. – Martijn Pieters Jul 29 '13 at 16:11