Regex.Matches returns full result in 0 position

Question

The following:

Regex.Matches("Some Text @param Some More", "(.*)(@param)(.*)")

returns

Some Text @param Some More
Some Text
@param
Some More

Is there any way to not have the first line? I cannot find any documentation on this. And, if I use online parsers, they only list the 3 groups...I would like to avoid having to code in the ignore first...

Just `Skip(1)` after your matches. This is the normal behaviour of pretty much all Regex tools. — Simon Belanger, Jul 29 '13 at 19:12
Because when I ask for my match groups, I expect the groups () — Justin Pihony, Jul 29 '13 at 19:12
@SimonBelanger I would be ok with that if I could. GroupCollection is not letting me run the enumerable extensions....I know the documentation says it is IEnumerable, but the IDE yells... — Justin Pihony, Jul 29 '13 at 19:16
@JustinPihony Do `Regex.Matches.OfType` to access the enumerable extensions — Simon Belanger, Jul 29 '13 at 19:17
@SimonBelanger Post that as an answer and I will accept. OfType is what I was missing — Justin Pihony, Jul 29 '13 at 19:19

score 2 · Accepted Answer · answered Jul 29 '13 at 19:29

2

Use a named group captures to not have to work with indexing. Change to this:

Regex.Matches("Some Text @param Some More", "(?<One>.*)(@param)(?<Two>.*)")

then access the match data such as

var data1 = mt.Groups["One"].Value;
var data2 = mt.Groups["Two"].Value;

answered Jul 29 '13 at 19:29

ΩmegaMan

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Choosing as the answer as this is the best to answer my question directly. I ended up going with the skip option once I used OfType, though – Justin Pihony Jul 29 '13 at 19:47
@JustinPihony index 0 is always the full match regardless of submatches. Then in order of match each index thereafter is each of the submatches. That is true on every match. By using named match captures one doesn't have to figure out which sub match is which. – ΩmegaMan Jul 29 '13 at 20:13

Casimir et Hippolyte · Answer 2 · 2013-07-29T19:22:56.810

1

Try this:

Regex.Matches("Some Text @param Some More", "^.*(?=@param)|@param|(?<=@param).*");

edited Jul 29 '13 at 19:22

answered Jul 29 '13 at 19:16

Casimir et Hippolyte

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Nope, this does not work – Justin Pihony Jul 29 '13 at 19:20
@JustinPihony: retry now. – Casimir et Hippolyte Jul 29 '13 at 19:21

Regex.Matches returns full result in 0 position

2 Answers2