Opening default android browser with a URL and parameter passing in android

Question

I'm trying to pass on a URL of the form:

to the Android Browser, however, once this URL is sent to the browser in this form exactly,

the browser seems to append a forward slash to the URL itself as follows:

And surprisingly, the android browser is having trouble parsing this. I'm not sure why this breaks the URL.

The invoking code is this:

Intent sampleIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(sampleURL));
startActivity(sampleIntent);

Is this a bug with the Android browser or do I need to do something differently here?

In the browser address bar I see the second URL with an additional slash. If I remove the '?' only than it seems to work correctly — Grammaton, Jul 31 '13 at 06:30
@Stacks28 I think this is the same as what I'm doing, no difference. — Grammaton, Jul 31 '13 at 06:45

score 0 · Answer 1 · edited May 23 '17 at 12:31

If you closely read How can I open android browser with specified POST parameters? question and the comments, I think you might get an answer. Basically it says that you cannot add extra params to POST to start the browser using Intent, however GET allows that. There is also a solution by @Pete for doing what you wish, inside a WebView(if that what you might want to consider):

WebView webview = new WebView(this);
setContentView(webview);
byte[] post = EncodingUtils.getBytes("postvariable=value&nextvar=value2", "BASE64");
webview.postUrl("http://www.geenie.nl/AnHeli/mobile/ranking/demo/index.php", post)

Hope this helps in someway.

Update

Check out Opening URL on Android web browser causes Google search question. It talks about using URLEncoder.encode before passing in the URL. It might help.

I actually want to close the application itself & only have a page with this url opened. So opening a webview may not be a great solution for me. — Grammaton, Jul 31 '13 at 06:41

Opening default android browser with a URL and parameter passing in android

1 Answers1