create a link with xslt in html to other html

Question

I have the following xml code:

<?xml version="1.0" encoding="UTF-8"?>
<?xml-model href="http://www.tei-c.org/release/xml/tei/custom/schema/relaxng/tei_all.rng" type="application/xml" schematypens="http://relaxng.org/ns/structure/1.0"?>
<?xml-model href="http://www.tei-c.org/release/xml/tei/custom/schema/relaxng/tei_all.rng" type="application/xml"
        schematypens="http://purl.oclc.org/dsdl/schematron"?>
<TEI xmlns="http://www.tei-c.org/ns/1.0">
    <teiHeader/>
    <text>
        <head n="3">Capitulo primeyro</head>
        <pb facs="folio16r.jpg"/>
        <div>
            <p>... figurado <app>
                <lem>pollo</lem>
                <rdg wit="#A">pollo</rdg>
                <rdg wit="#B">pello</rdg>
            </app> Parayso ...</p>
            <p> ... <app>
                <lem>sacarõ</lem>
                <rdg wit="#A">sacarõ</rdg>
                <rdg wit="#B">ssaee</rdg>
                </app> ...</p>
        </div>
        <pb facs="folio16v.jpg"/>
        <div>
            <p> .... os fisicos <app>
                <lem>dessesperarom</lem>
                <rdg wit="#A">desseperarom</rdg>
                <rdg wit="#B">desesperõ</rdg>
                </app> ... que assy <app>
                <lem>saa</lem>
                <rdg wit="#A">sooa</rdg>
                <rdg wit="#B">saa</rdg>
                </app> ...</p>
        </div>
    </body>
</text>

With my XSL I already obtain 3 different HTML (one for A, one for B and one with lemma). I created a template in XSL for app:

<xsl:template match="app">
    <xsl:variable name="appNumber" select="count(preceding::app) + 1"/>
    <a href="#app_{$appNumber}"><xsl:apply-templates select="lem"/></a>
</xsl:template>

<xsl:template match="app" mode="footnote">
    <xsl:variable name="appNumber" select="count(preceding::app) + 1"/>
    <li id="app_{$appNumber}">
        <xsl:for-each select="rdg">
            <i><xsl:apply-templates/></i><xsl:text> </xsl:text>
            <a>
                <xsl:attribute name="href">
                    <xsl:text>#</xsl:text>
                    <xsl:apply-templates select="app"/>
                </xsl:attribute>
                <xsl:value-of select="substring-after(@wit, '#')">
                </xsl:value-of>
            </a>
            <xsl:text> </xsl:text>
            <br/>
            <xsl:if test="position() lt last()"></xsl:if>
        </xsl:for-each>
    </li>
</xsl:template>

Now I have this html:

<ul>
    <li id="app_1"><i>prophetas</i> <a href="#">Editor</a> <br /><i>prophetas</i> <a href="#">A</a> <br /></li>
    <li id="app_2"><i>pollo</i> <a href="#">Editor</a> <br /><i>pollo</i> <a href="#">A</a> <br /></li>
    <li id="app_3"><i>sacarõ</i> <a href="#">Editor</a> <br /><i>sacarõ</i> <a href="#">A</a> <br /></li>
    <li id="app_4"><i>dessesperarom</i> <a href="#">Editor</a> <br /><i>desseperarom</i> <a href="#">A</a> <br /></li>
    <li id="app_5"><i>saa</i> <a href="#">Editor</a> <br /><i>sooa</i> <a href="#">A</a> <br /></li>
    <li id="app_6"><i>ante</i> <a href="#">Editor</a> <br /><i>ante</i> <a href="#">A</a> <br /></li>
</ul>

As you see a start to create a link in the li but I don't get what I want. I would like to say that the link goes from the wit (#A or #B or #Editor) to the same point of text in the other html. For example if I am looking a A html, in app, clicking on B I want to go to same point of text in B html. Can any one help?

Your explanation is very confusing. How about writing down the HTML you want to get? — Tomalak, Aug 03 '13 at 09:59
Also, whilst it is always good not to have a large XML sample, I think you are not showing enough here, as your current output does not correspond to your current input. It looks like your input XML should have six **app** elements, with different text in to what you have shown us. If you could show the XML you are currently using to get your current output, that would help a lot too. Thanks! — Tim C, Aug 03 '13 at 10:58

score 0 · Answer 1 · answered Nov 17 '17 at 10:23

If I get it right, this is only about the right composition of the link. It seems you have one apparatus file which should be linked to the different source files on each apparatus entry. Actually, you were quite close. Try this:

<xsl:attribute name="href">
    <xsl:value-of select="substring-after(@wit, '#')"/>
    <xsl:text>.html#app_</xsl:text>
    <xsl:value-of select="$appNumber"/>
    <xsl:apply-templates select="app"/>
</xsl:attribute>

This will produce links like this:

<a href="A.html#app_2">A</a>

I assume you have already figured it out for yourself after all the time. I wanted to answer this nonetheless, maybe it is still useful for someone.

create a link with xslt in html to other html

1 Answers1