How to construct the Scala Form using a Java class in Play

Question

I have a Java class like:

public class User {
   public String name;
   public String email;
}

Instead of creating another case class in Scala or using tuple, can I do something like

Form<User> form = Form.form(User.class)

The above code is possible in Play Java but not for Scala

Just an idea, but should work: What happens if you just import the Java form class and use it (i.e. use `play.data.Form` instead of the default one for Scala, `play.api.data.Form`)? You should be able to use that one from Scala exactly like from Java. Well, almost exactly, more like `form:Form[User] = Form.form(User.class)` — Carsten, Aug 05 '13 at 18:52
http://stackoverflow.com/questions/1135248/scala-equivalent-of-java-java-lang-classt-object — Carsten, Aug 05 '13 at 19:50

score 2 · Accepted Answer · answered Aug 05 '13 at 19:53

2

.class isn't a keyword in Scala. Try classOf[User].

i.e.

val form = Form.form(classOf[User])

answered Aug 05 '13 at 19:53

Luigi Plinge

1 Answers1