Foreach two array in one time

Question

I want to generate a selectbox using two arrays, one containing the country codes and another containing the country names.

This is an example:

<?php

$codes = array('tn','us','fr');

$names = array('Tunisia','United States','France');

foreach( $codes as $code and $names as $name ) {

echo '<option value="' . $code . '">' . $name . '</option>';

}

?>

This method didn't work for me. any suggestions?

Thanks

So you don't even take the time to search on this site before asking? http://stackoverflow.com/questions/4480803/two-arrays-in-foreach-loop — , Aug 07 '13 at 05:22
How is it that you're copy and paste reposting the exact same question?! — deceze, Aug 07 '13 at 05:27

score 5 · Answer 1 · edited Oct 19 '14 at 17:42

It has to be 2 arrays? is more easy if you just use an associative array.

like:

$countries = array('tn'=> "Tunisia", "us"=>'United States',"fr"=>'France');
foreach($countries as $code=>$name) {
     echo '<option value="' . $code . '">' . $name . '</option>';    
}

if you already have those two arrays, you can combine them:

$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');
$countries = array_combine($codes, $names);

Here is a demo: http://codepad.org/nYjCk3uQ

score 2 · Answer 2 · answered Aug 07 '13 at 05:22

if you are same size of array you can use like below

<?php

$codes = array('tn','us','fr');

$names = array('Tunisia','United States','France');
$i=0
foreach( $names as $name ) {

echo '<option value="' . $codes [$i] . '">' . $name . '</option>';
  $i = $i+1    
}

?>

score 2 · Answer 3 · answered Aug 07 '13 at 05:24

if both arrays are perfectly indexed then you can iterate one array alone

for($i=0; $i<count($codes);$i++) {

echo '<option value="' . $code[$i] . '">' . $name[$i] . '</option>';

}

This will only work if both the arrays are having matching indexes on their values

score 2 · Answer 4 · edited Jun 20 '20 at 09:12

All fully tested

3 ways to create a dynamic dropdown from an array.

This will create a dropdown menu from an array and automatically assign its respective value.

Method #1 (Normal Array)

<?php

$names = array('tn'=>'Tunisia','us'=>'United States','fr'=>'France');

echo '<select name="countries">';

foreach($names AS $let=>$word){
    echo '<option value="'.$let.'">'.$word.'</option>';
}
echo '</select>';
 
?>

Method #2 (Normal Array)

<select name="countries">

<?php

$countries = array('tn'=> "Tunisia", "us"=>'United States',"fr"=>'France');
foreach($countries as $select=>$country_name){
echo '<option value="' . $select . '">' . $country_name . '</option>';
}
?>

</select>

Method #3 (Associative Array)

<?php

$my_array = array(
     'tn' => 'Tunisia',
     'us' => 'United States',
     'fr' => 'France'
);

echo '<select name="countries">';
echo '<option value="none">Select...</option>';
foreach ($my_array as $k => $v) {
    echo '<option value="' . $k . '">' . $v . '</option>';
}
echo '</select>';
?>

Code Lღver · Answer 5 · 2013-08-07T05:29:02.423

Use the for loop for two arrays:

$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');
$i = 0;
$length = count($codes);
for($i;$i<$length;$i++) {
    echo '<option value="' . $code[$i] . '">' . $name[$i] . '</option>';
}

This will work for you.

Another ways is here:

$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');
$newarr = array_combine($codes,$names);
foreach($newarr as $index => $value){
    echo '<option value="' . $index . '">' . $value . '</option>';
}

score 1 · Answer 6 · answered Aug 07 '13 at 05:23

1

foreach( $codes as $index => $code ) {
   echo '<option value="' . $code . '">' . $names[$index] . '</option>';
}

answered Aug 07 '13 at 05:23

Prasannjit

795
4
11

score 0 · Answer 7 · answered Aug 07 '13 at 05:23

I would approach it like:

$names = array('Tunisia' : 'tn','United States' :'us','France': 'fr');
foreach($names as $key=>$value) {
echo '<option value="' . $value . '">' . $key . '</option>';
}

Another way can be:

$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');
$count=0
foreach( $names as $name ) {
echo '<option value="' . $codes [$i] . '">' . $name . '</option>';
  $count = $count + 1;  
}

score 0 · Answer 8 · answered Aug 07 '13 at 05:24

0

Try this

 foreach( $codes as $index => $code ) {
    echo '<option value="' . $code . '">' . $names[$index] . '</option>';
     }

answered Aug 07 '13 at 05:24

Padmanathan J

4,614
5
37
75