How to display multiple notifications in android

Question

I am receiving only one notification and if there comes another notification, it replaces the previous one and here is my code

private static void generateNotification(Context context, String message,
        String key) {
    int icon = R.drawable.ic_launcher;
    long when = System.currentTimeMillis();
    NotificationManager notificationManager = (NotificationManager) context
            .getSystemService(Context.NOTIFICATION_SERVICE);
    Notification notification = new Notification(icon, message, when);

    String title = context.getString(R.string.app_name);

    Intent notificationIntent = new Intent(context,
            FragmentOpenActivity.class);
    notificationIntent.putExtra(key, key);
    // set intent so it does not start a new activity
    notificationIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP
            | Intent.FLAG_ACTIVITY_SINGLE_TOP);
    PendingIntent intent = PendingIntent.getActivity(context, 0,
            notificationIntent, 0);
    notification.setLatestEventInfo(context, title, message, intent);
    notification.flags |= Notification.FLAG_AUTO_CANCEL;

    notification.defaults |= Notification.DEFAULT_SOUND;

    // notification.sound = Uri.parse("android.resource://" +
    // context.getPackageName() + "your_sound_file_name.mp3");
    notification.defaults |= Notification.DEFAULT_VIBRATE;
    notificationManager.notify(0, notification);

}

As per official Document,you should not show multiple notifications from one app you have to stack all the notifications.. Have a look: http://developer.android.com/design/patterns/notifications_k.html — Gowtham Kumar, Feb 26 '15 at 12:30

score 149 · Answer 1 · answered Aug 07 '13 at 11:23

149

just replace your line with this

 notificationManager.notify(Unique_Integer_Number, notification);

hope it will help you.

answered Aug 07 '13 at 11:23

Sanket Shah

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3

what is `Unique_Integer_Number` in your code.. and which code it should replace – Kartheek Sarabu Aug 07 '13 at 12:50
4

Unique integer number means you have to set integer value that will never repeated. example 0,1,2,3,4,5,....!!!! – Sanket Shah Aug 07 '13 at 12:57
2

notificationManager.notify(1, notification); notificationManager.notify(2, notification); – Sanket Shah Aug 07 '13 at 12:58
1

How will increment automatically as notification comes?? – Mitesh Shah Jun 12 '14 at 13:25
As you make notification. @Mitesh – Sanket Shah Jun 13 '14 at 06:17
When I try this I get the new notification replacing the old one, unique id or not. Furthermore they don't stack. – Michael Feb 16 '16 at 02:28
If you are using same Notification ID then and then only it will replace your previous Notification but if you are using unique ID then it will surely create a new one notification. @Michael – Sanket Shah Feb 16 '16 at 03:57
23

generating unique integer: (int) ((new Date().getTime() / 1000L) % Integer.MAX_VALUE); – Andrii Kovalchuk Jun 13 '16 at 19:49
my phone is hang when i am updating status of multiple notifications simultaneously – H Raval Aug 03 '16 at 11:07
Not work for me, there only label change not show two notifications on task bar – Sumit Pathak Oct 17 '16 at 10:58
@SumitPathak share your code otherwise i can't understand your problem – Sanket Shah Oct 24 '16 at 06:02
1

Does this have any sideeffects ? – HopefullyHelpful Jan 12 '17 at 10:50
@HopefullyHelpful Nope...! Its doesn't. – Sanket Shah Jan 23 '17 at 09:29
@Andrain... will never be repeated in what context? Is it in the same app instance period? then there is a small loop hole here that notification persist even after the app instance. – Sreekanth Karumanaghat Aug 22 '17 at 09:27
@SreekanthKarumanaghat Notification will not repeat the same number until the user removes the notification – Sanket Shah Aug 23 '17 at 05:53
How does that work? Can you please explain the underlying logic? – Sreekanth Karumanaghat Aug 23 '17 at 08:41
@tieorange in my case the number is not unique when there are multiple alarms triggered in a queue where in I create notification, gettime seems ignoring millsecs – Naga Nov 13 '18 at 17:15

score 95 · Answer 2 · edited Dec 02 '16 at 15:17

95

Simple notification_id needs to be changable.

Just create random number for notification_id.

    Random random = new Random();
    int m = random.nextInt(9999 - 1000) + 1000;

or you can use this method for creating random number as told by tieorange (this will never get repeated):

    int m = (int) ((new Date().getTime() / 1000L) % Integer.MAX_VALUE);

and replace this line to add parameter for notification id as to generate random number

    notificationManager.notify(m, notification);

edited Dec 02 '16 at 15:17

Hammad Nasir

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answered Nov 04 '14 at 10:36

sagar.android

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A bit hacky and runs into the possibility that you will end up with the same notification id, but this works if you need something really quick. – Muhammad Abdul-Rahim Nov 05 '15 at 16:24
2

If I see this right, the apporach from tieorange only works with seconds. So if you have multiple notifications at the same second, this will not work. – testing Sep 12 '17 at 16:01
2

@testing is right. thats why I have a 2nd step, m += random.nextInt(100) + 1; this might be one step extra but its way safer. I saw the above method fail in the last mins of an Auction/Bidding app. Hence i added another line for safety! – user3833732 Mar 13 '18 at 09:07
1

can also use current timestamp System.currentTimeMillis().toInt() – Nitin Feb 22 '22 at 18:49

score 28 · Answer 3 · answered Oct 20 '14 at 12:03

28

Using Shared Preferences worked for me

SharedPreferences prefs = getSharedPreferences(Activity.class.getSimpleName(), Context.MODE_PRIVATE);
int notificationNumber = prefs.getInt("notificationNumber", 0);
...

notificationManager.notify(notificationNumber , notification);
SharedPreferences.Editor editor = prefs.edit();
notificationNumber++;
editor.putInt("notificationNumber", notificationNumber);
editor.commit();

answered Oct 20 '14 at 12:03

vLopez

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This is a fairly smart way to do it if you need to keep track of every notification sent as well. Probably one of the smarter answers here. – Muhammad Abdul-Rahim Nov 05 '15 at 16:28

score 13 · Answer 4 · answered Jan 07 '17 at 02:52

13

Replace your line with this.

notificationManager.notify((int) ((new Date().getTime() / 1000L) % Integer.MAX_VALUE), notification);

answered Jan 07 '17 at 02:52

Tony Baby

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Doesn't removing notification of a particular payload type gets difficult with this approach? – Sethuraman Srinivasan Jan 13 '20 at 23:45

score 9 · Answer 5 · answered Sep 27 '15 at 15:42

i guess this will help someone..
in below code "not_nu" is an random int.. PendingIntent and Notification have the same ID .. so that on each notification click the intent will direct to different activity..

private void sendNotification(String message,String title,JSONObject extras) throws JSONException {
   String id = extras.getString("actionParam");
    Log.e("gcm","id  = "+id);
    Intent intent = new Intent(this, OrderDetailActivty.class);
    intent.putExtra("id", id);
    intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
    final int not_nu=generateRandom();
    PendingIntent pendingIntent = PendingIntent.getActivity(this, not_nu /* Request code */, intent,
            PendingIntent.FLAG_ONE_SHOT);

    Uri defaultSoundUri= RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
    NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this)
            .setSmallIcon(R.mipmap.ic_cart_red)
            .setContentTitle(title)
            .setContentText(message)
            .setAutoCancel(true)
            .setSound(defaultSoundUri)
            .setContentIntent(pendingIntent);

    NotificationManager notificationManager =
            (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);

    notificationManager.notify(not_nu /* ID of notification */, notificationBuilder.build());
}
public int generateRandom(){
    Random random = new Random();
    return random.nextInt(9999 - 1000) + 1000;
}

My notifications are not stacking still, is there any specific things I ahve to do besides what you show here? — Lion789, Oct 07 '16 at 07:05
What is that random.nextInt calculation doing there...can you explain??? 9999-1000???? what is that... — Radu, Nov 30 '17 at 11:36
@Radu as you can see in the code "notificationManager.notify( " takes an int ( ID for notification ) as the first parameter. if this Int ( ID ) is same for new notification it will replace the old one and shows the new. if this Int(ID) is different then the new notification is treated separately and shows as stacks. so the older notification stays. and to achieve this. we are creating random int and assigning as ID. "random.nextInt(9999 - 1000) + 1000;" using this code. — Muneef M, Dec 09 '17 at 16:18
@Lion789 you just have to use different ID for new notifications then it should stack up the notifications. — Muneef M, Dec 09 '17 at 16:22
new NotificationCompat.Builder(this); is deprecated in Android Oreo, Please check docs and use Notification Channel implementation. — TapanHP, Apr 26 '18 at 06:31

score 5 · Answer 6 · edited May 20 '16 at 13:16

5

At the place of uniqueIntNo put unique integer number like this:

mNotificationManager.notify(uniqueIntNo, builder.build());

edited May 20 '16 at 13:16

gvuksic

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answered May 20 '16 at 12:10

Sachin Singh

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score 5 · Answer 7 · edited Jan 11 '20 at 18:50

5

notificationManager.notify(0, notification);

Put this code instead of 0

new Random().nextInt()

Like below it works for me

notificationManager.notify(new Random().nextInt(), notification);

edited Jan 11 '20 at 18:50

mehdi

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answered Jan 23 '19 at 11:33

Sameer Ahmed Mallah

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From Review: Hi, please don't answer just with source code. Try to provide a nice description about how your solution works. See: [How do I write a good answer?](https://stackoverflow.com/help/how-to-answer). Thanks – sɐunıɔןɐqɐp Jan 23 '19 at 11:38

score 4 · Answer 8 · answered Aug 07 '13 at 13:09

4

You need to add a unique ID to each of the notifications so that they do not combine with each other. You can use this link for your reference :

https://github.com/sanathe06/AndroidGuide/tree/master/ExampleCompatNotificationBuilder

answered Aug 07 '13 at 13:09

arshu

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score 3 · Accepted Answer · answered Jan 18 '14 at 05:39

I solved my problem like this...

/**
     * Issues a notification to inform the user that server has sent a message.
     */
    private static void generateNotification(Context context, String message,
            String keys, String msgId, String branchId) {
        int icon = R.drawable.ic_launcher;
        long when = System.currentTimeMillis();
        NotificationCompat.Builder nBuilder;
        Uri alarmSound = RingtoneManager
                .getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
        nBuilder = new NotificationCompat.Builder(context)
                .setSmallIcon(R.drawable.ic_launcher)
                .setContentTitle("Smart Share - " + keys)
                .setLights(Color.BLUE, 500, 500).setContentText(message)
                .setAutoCancel(true).setTicker("Notification from smartshare")
                .setVibrate(new long[] { 100, 250, 100, 250, 100, 250 })
                .setSound(alarmSound);
        String consumerid = null;
        Integer position = null;
        Intent resultIntent = null;
        if (consumerid != null) {
            if (msgId != null && !msgId.equalsIgnoreCase("")) {
                if (key != null && key.equalsIgnoreCase("Yo! Matter")) {
                    ViewYoDataBase db_yo = new ViewYoDataBase(context);
                    position = db_yo.getPosition(msgId);
                    if (position != null) {
                        resultIntent = new Intent(context,
                                YoDetailActivity.class);
                        resultIntent.putExtra("id", Integer.parseInt(msgId));
                        resultIntent.putExtra("position", position);
                        resultIntent.putExtra("notRefresh", "notRefresh");
                    } else {
                        resultIntent = new Intent(context,
                                FragmentChangeActivity.class);
                        resultIntent.putExtra(key, key);
                    }
                } else if (key != null && key.equalsIgnoreCase("Message")) {
                    resultIntent = new Intent(context,
                            FragmentChangeActivity.class);
                    resultIntent.putExtra(key, key);
                }.
.
.
.
.
.
            } else {
                resultIntent = new Intent(context, FragmentChangeActivity.class);
                resultIntent.putExtra(key, key);
            }
        } else {
            resultIntent = new Intent(context, MainLoginSignUpActivity.class);
        }
        PendingIntent resultPendingIntent = PendingIntent.getActivity(context,
                notify_no, resultIntent, PendingIntent.FLAG_UPDATE_CURRENT);
        if (notify_no < 9) {
            notify_no = notify_no + 1;
        } else {
            notify_no = 0;
        }
        nBuilder.setContentIntent(resultPendingIntent);
        NotificationManager nNotifyMgr = (NotificationManager) context
                .getSystemService(context.NOTIFICATION_SERVICE);
        nNotifyMgr.notify(notify_no + 2, nBuilder.build());
    }

score 3 · Answer 10 · answered Sep 08 '14 at 10:35

3

Another way of doing it is take the current date convert it into long just take the last 4 digits. There is a high probability that the number will be unique.

    long time = new Date().getTime();
    String tmpStr = String.valueOf(time);
    String last4Str = tmpStr.substring(tmpStr.length() -5);
    int notificationId = Integer.valueOf(last4Str);

answered Sep 08 '14 at 10:35

Vidyadhara

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Why use just the last four digits and not the datetime itself? – Muhammad Abdul-Rahim Nov 05 '15 at 16:27
4

Here is a bit shorter code: `int notificationId = System.currentTimeMillis()%10000;` – bvk256 Dec 11 '15 at 14:47
why only 4 digits? – Pavel Biryukov Apr 28 '16 at 07:58

score 3 · Answer 11 · answered Jul 24 '19 at 12:03

3

You just need to change your one-line from notificationManager.notify(0, notification); to notificationManager.notify((int) System.currentTimeMillis(), notification);...

This will change the id of notification whenever the new notification will appear

answered Jul 24 '19 at 12:03

Arun Sriramula

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1
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score 0 · Answer 12 · edited Nov 09 '15 at 19:46

The problem is with your notificationId. Think it as an array index. Each time you update your notification, the notificationId is the place it takes to store value. As you are not incrementing your int value (in this case, your notificationId), this always replaces the previous one. The best solution I guess is to increment it just after you update a notification. And if you want to keep it persistent, then you can store the value of your notificationId in sharedPreferences. Whenever you come back, you can just grab the last integer value (notificationId stored in sharedPreferences) and use it.

score 0 · Answer 13 · edited Jan 12 '20 at 06:26

Below is the code for pass unique notification id:

//"CommonUtilities.getValudeFromOreference" is the method created by me to get value from savedPreferences.
String notificationId = CommonUtilities.getValueFromPreference(context, Global.NOTIFICATION_ID, "0");
int notificationIdinInt = Integer.parseInt(notificationId);

notificationManager.notify(notificationIdinInt, notification);

// will increment notification id for uniqueness
notificationIdinInt = notificationIdinInt + 1;
CommonUtilities.saveValueToPreference(context, Global.NOTIFICATION_ID, notificationIdinInt + "");
//Above "CommonUtilities.saveValueToPreference" is the method created by me to save new value in savePreferences.

Reset notificationId in savedPreferences at specific range like I have did it at 1000. So it will not create any issues in future. Let me know if you need more detail information or any query. :)

hello can you post full code well we know to generate multiple notification need unique id but after generate we also have to cancel that particular notification .. there is problem to save and get each unique id in my case if you can help pls — Jayman Jani, Jan 19 '17 at 06:38

score 0 · Answer 14 · edited Jan 13 '20 at 03:15

Use the following method in your code.

Method call :-

notificationManager.notify(getCurrentNotificationId(getApplicationContext()), notification);

Method:-

  *Returns a unique notification id.
         */

        public static int getCurrentNotificationId(Context iContext){

            NOTIFICATION_ID_UPPER_LIMIT = 30000; // Arbitrary number.

            NOTIFICATION_ID_LOWER_LIMIT = 0;
            SharedPreferences sharedPreferences = PreferenceManager.getDefaultSharedPreferences(iContext);
        int previousTokenId= sharedPreferences.getInt("currentNotificationTokenId", 0);

        int currentTokenId= previousTokenId+1;

        SharedPreferences.Editor editor= sharedPreferences.edit();

        if(currentTokenId<NOTIFICATION_ID_UPPER_LIMIT) {

            editor.putInt("currentNotificationTokenId", currentTokenId); // }
        }else{
            //If reaches the limit reset to lower limit..
            editor.putInt("currentNotificationTokenId", NOTIFICATION_ID_LOWER_LIMIT);
        }

        editor.commit();

        return currentTokenId;
    }

score 0 · Answer 15 · answered Oct 10 '20 at 10:05

0

For Kotlin.

 notificationManager.notify(Calendar.getInstance().timeInMillis.toInt(),notificationBuilder.build())

answered Oct 10 '20 at 10:05

Jayant Dhingra

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score -1 · Answer 16 · answered Dec 20 '17 at 09:53

-1

A simple counter may solve your problem.

private Integer notificationId = 0;

private Integer incrementNotificationId() {
   return notificationId++;
}

NotificationManager.notify(incrementNotificationId, notification);

answered Dec 20 '17 at 09:53

nirfrea

84
3

score -1 · Answer 17 · edited Jul 14 '18 at 08:54

-1

declare class member
static int i = 0;

mNotificationManager.notify(++i, mBuilder.build());

edited Jul 14 '18 at 08:54

juzraai

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answered Jul 14 '18 at 08:20

amar

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EdgeDev · Answer 18 · 2018-09-26T14:03:39.047

-1

val notifyIdLong = ((Date().time / 1000L) % Integer.MAX_VALUE)
var notifyIdInteger = notifyIdLong.toInt()
if (notifyIdInteger < 0) notifyIdInteger = -1  * notifyIdInteger // if it's -ve change to positive
notificationManager.notify(notifyIdInteger, mBuilder.build())
log.d(TAG,"notifyId = $notifyIdInteger")

edited Sep 26 '18 at 14:03

answered Sep 26 '18 at 13:56

EdgeDev

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score -1 · Answer 19 · edited Oct 20 '21 at 23:45

-1

val notificationId = System.currentTimeMillis().toInt()
val i = Intent(applicationContext, HomeActivity::class.java)
val pendingIntent =
    PendingIntent.getActivity(this, notificationId, i, PendingIntent.FLAG_CANCEL_CURRENT)
//put notification id in pending intent and for notify manager.

mNotificationManager.notify(num, notificationnn)

edited Oct 20 '21 at 23:45

Cody Gray - on strike

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answered Oct 19 '21 at 07:58

Abhay kumar bhumihar

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How to display multiple notifications in android

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