Change date 2013-08-09 => 09-Aug-2013

Question

I want to change format of date by 2013-08-09 to 09-Aug-2013, I tried this:

echo $date=date("Y-m-d");
//output 2013-08-09
echo date("d-M-Y",mktime(0-0-0,$date));

but this code showing 10-Aug-2013 I dont know why this showing date 10 instead of 09.

Answer would be highly appreciated , thanks in advance

Why do not simply look into manual: http://php.net/manual/en/function.date.php ?? — Alma Do, Aug 09 '13 at 13:41
your `mktime()` call is completely and utterly wrong. I suspect you intended to use `strtottime()` instead, but the way you're doing it would be badly wrong even for that. I suggest reading some basic examples from the manual. — Spudley, Aug 09 '13 at 13:45

score 6 · Accepted Answer · answered Aug 09 '13 at 13:41

6

following is easier:

echo date("d-M-Y",strtotime($date));

at mktime you have to subtract one day

answered Aug 09 '13 at 13:41

Patrick Brösamle

Thanks Patrick, why was it showing next from current date. – Dinesh Aug 09 '13 at 13:44
look here for the answer [link](http://php.net/manual/en/function.mktime.php) can't tell you in short sry – Patrick Brösamle Aug 09 '13 at 13:48
Thanks its realy awesome, but i dont knw y my question being downvoted. – Dinesh Aug 09 '13 at 14:00

score 1 · Answer 2 · answered Aug 09 '13 at 13:45

1

You aren't passing in the parameters to mktime properly. mktime requires 6 integer parameters where as you have 1 integer and 1 string here.

Try using a DateTime object instead:

$date = new DateTime();
echo $date->format('d-M-Y');

answered Aug 09 '13 at 13:45

rink.attendant.6

+1 for very good explanation...Thanks for knowledge... :) – Dinesh Aug 09 '13 at 14:05

2 Answers2