Just got confused with parent pid value in child process block. My program is given below:
int main(int argc, char *argv[])
{
pid_t pid;
pid=fork();
if(pid==-1){
perror("fork failure");
exit(EXIT_FAILURE);
}
else if(pid==0){
printf("pid in child=%d and parent=%d\n",getpid(),getppid());
}
else{
printf("pid in parent=%d and childid=%d\n",getpid(),pid);
}
exit(EXIT_SUCCESS);
}
Output: pid in parent=2642 and childid=2643
pid in child=2643 and parent=1
In "Advanced Unix programming" it says that child process can get parent process id using getppid() function. But here I am getting "1" which is "init" process id.
How can I get the parent pid value in the child process block.. Please help me in getting output.
I executed in "Linux Mint OS" but in "WindRiver" OS I am not getting this problem. Does this program change behaviour according to OS?