Deploying CXF webservices in Tomcat

Question

I am trying to deploy a web service in Tomcat7 using maven.

Below I provide some configuration info:

web.xml

...
<servlet-mapping>
   <servlet-name>CXFServlet</servlet-name>
   <url-pattern>/services/*</url-pattern>
</servlet-mapping>
...

pom.xml

...
<build>
        <plugins>
            <plugin>
                <groupId>org.codehaus.mojo</groupId>
                <artifactId>tomcat-maven-plugin</artifactId>
                <version>1.1</version>
                <configuration>
                    <url>http://localhost:8080/manager/text</url>
                    <server>TomcatServer</server>
                    <path>/services/userinfo</path>
...

Given the <url-pattern>/services/*</url-pattern> and <path>/services/userinfo</path> configuration, the URL http://localhost:8080/services/userinfo shows 404.

If using instead <url-pattern>/*</url-pattern> everything works as expected (i.e. http://localhost:8080/services/userinfo shows the list of available methods).

The question:

Why /services/* doesn't work in my case?

Patrick · Accepted Answer · 2013-08-11T17:26:23.597

1

The path in your tomcat-maven-plugin configuration

<path>/services/userinfo</path>

defines where you are deploying the webapp (the context root). In this case, you are deploying it to

http://localhost:8080/services/userinfo

Check out the webapps directory in your Tomcat installation.

Since you are defining the CXFServlet mapping as /services/*, the CXF service list would show at

http://localhost:8080/services/userinfo/services/

When you re-defined the mapping to /*, it just appeared to work as expected, but that was only because the context root you used and the service listing path you expected were the same.

edited Aug 11 '13 at 17:26

answered Aug 11 '13 at 16:19

Patrick

2,102
15
11

The full URL for my service is `http://localhost:8080/services/userinfo/UserInfoService` (I didn't show the `cxf-servlet.xml` since it doesn't play a role here). The service list appears at: `http://localhost:8080/services/userinfo/`. If I understand correctly the specification of wildcard `/services/*` will work for any subdirectory under the `services` path. BTW the generated war has the name `services#userinfo.war`. – Eugen Aug 11 '13 at 17:14
1

If you change the mapping back to `/services/*`, does the service listing show at `http://localhost:8080/services/userinfo/services`? That is what I would expect. The services#userinfo.war name is what maps your webapp to `http://localhost:8080/services/userinfo/`, regardless of CXF or the servlet mapping. – Patrick Aug 11 '13 at 17:21
Yes it does. I thought that the matching starts immediately after the port number. – Eugen Aug 11 '13 at 18:48
The matching starts after the webapp's context root, which for your application is `/services/userinfo/`. If you want this application to run as Tomcat's ROOT context (i.e right at `http://localhost:8080/`), you will need configure Tomcat for that. – Patrick Aug 11 '13 at 18:54
1

[This link](http://stackoverflow.com/questions/715506/tomcat-6-how-to-change-the-root-application) might help if you have questions changing the ROOT webapp. – Patrick Aug 11 '13 at 19:05

Deploying CXF webservices in Tomcat

1 Answers1