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I am getting a value from server that is not containing any Floating point let say its 1234 and have to cvonvert it in Floating value with 2 decimal point like 12.34.

Right now what i am doing is getting value storing it in float that convert the current value 1234 to 1234.0 after that doing this 

tempB=Math.floor(tempB)/100.0;
DecimalFormat df = new DecimalFormat("###.##");
RewardsBalance=df.format(tempB);

But with this i m having an issue that when i have value such that 1230 it results in 12.3 not that 12.30 but when i have value 1234 it gives the desired result that is 12.34 so what step i m missing any clue

Usman Kurd
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4 Answers4

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12.3 and 12.30 are the same value. The problem is not the value but the code that incorrectly converts the right value to the wrong representation. You probably want "###.00". With "#", zero shows as absent.

David Schwartz
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  • so you mean i should use format like "###.00" despite using ###.## ? – Usman Kurd Aug 12 '13 at 05:56
  • You should use '#' if you want a digit to appear unless it's a meaningless zero. You should use '0' if you want a digit to appear even if it's a meaningless zero. That's what the [docs](http://docs.oracle.com/javase/6/docs/api/java/text/DecimalFormat.html) say (see the section labelled "Special Pattern Characters"). – David Schwartz Aug 12 '13 at 05:59
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Use this it will work

Two digits after point

Community
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kalyan pvs
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Try this : 

String.format("%.2f", your_value);

It will do just like you want

Harish Godara
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0

try this

tempB=Math.floor(tempB)/100.0;
DecimalFormat df = new DecimalFormat("0.00");
df.format(tempB);

it will work fine.

balaji koduri
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