I'm having the hardest time with javascript regex, can't figure out how to match my url:
http://localhost:11111/#!/quote/18283
and
http://www.myurl.com/#!/quote/23834
with the same regex.
I just don't understand the regex rules that well.
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CSᵠ
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user2005259
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4What have been your attempts so far? – Jerry Aug 12 '13 at 20:39
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FYI - regex is entirely independent of other languages. Different languages use it differently, but something that is a correct RegEx match will be a correct RegEx match in Java, Javascript, C#, and thousands of others. – Xynariz Aug 12 '13 at 20:41
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possible duplicate of [Getting parts of a URL (Regex)](http://stackoverflow.com/questions/27745/getting-parts-of-a-url-regex) – Wrikken Aug 12 '13 at 20:44
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1What are you trying to achieve? Are you trying to extract some data from the URL? Anyway, `^http://\w+(\.\w+)*(:\d+)?/#!/(\w+/?)+$` would match both and all other urls having that structure. – plalx Aug 12 '13 at 20:52
2 Answers
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http://[\w\d\.:]+/#!/quote/\d{5} - but obviously that is without any other context.
I don't know what your negative cases are. Which parts of the URLs are important, etc, etc.
CodeBeard
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I just need the number at the end to vary in length, so I'm assuming I can change to http://[\w\d\.:]+/#!/quote/\d{1,10} and that will give me up to 10 digits. Thanks a lot – user2005259 Aug 12 '13 at 20:54
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1As with @Neil Neyman's answer above, you can use `\d+` instead of `\d{5}` to give yourself `1 or more` digits. – CodeBeard Aug 12 '13 at 20:57
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One hint I can add is, if you are only looking to match a specific domain.com with localhost you can use alternation (either/or) with the pipe | symbol like (this is just for one portion of the regex:
((www\.)?myurl\.com|localhost:\d+)
Neil Neyman
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