how to replace angel bracket string

Question

I need to replace all kinds of string that look like {\'\i} by just i

So I tried

String word = "something{\\\'\\\i}".replaceAll("\\\\{\\\'\\\i}", "DONE");

but it doesn't work, could anyone help me please?

Why are you trying to replace a different string than the one you've defined in your original string? — christopher, Aug 13 '13 at 11:02

Cephalopod · Accepted Answer · 2013-08-13T13:05:32.453

1

replaceAll expects regular expressions. Instead of trying to get the RegEx right, use replace.

String word = "something{\\'\\i}".replace("{\\'\\i}", "DONE");

edited Aug 13 '13 at 13:05

answered Aug 13 '13 at 11:06

Cephalopod

ok, you are right, thank you , but if i need to replace them all? it's just a part of the text... so i need to ask if it still contains and "replace" again until it doesnt cotain? – fatevil Aug 13 '13 at 11:16
`replace` does replace all occurrences of the text. – Cephalopod Aug 13 '13 at 11:17

score 0 · Answer 2 · answered Aug 13 '13 at 11:05

0

I think you have to use

String word = "yourtexthere"
String newWord = word.replaceAll("{\'\i}", "i");

answered Aug 13 '13 at 11:05

Gerret

Don't know what you mean ^^. Use word.replaceAll(%WHATYOUWANTTOREPLCE%, %WHATITSHOULDBE%). If you want all "{" replaced use: word.replaceAll("{", "i") for example. – Gerret Aug 13 '13 at 11:12

score 0 · Answer 3 · answered Aug 13 '13 at 11:11

0

Try this:

final String a = "text{\\'\\i}";
System.out.println(a);
System.out.println(a.replace("{\\'\\i}", "i"));

answered Aug 13 '13 at 11:11

r3ap3r

score 0 · Answer 4 · answered Aug 13 '13 at 11:11

0

You should simply use the replace function instead of replaceAll as the last one expects a regex as argument, Ex:

String word = "something{\\'\\i}".replace("{\\'\\i}", "'i' /* or i */");

\ has to be escaped in java, thats why we have \\

answered Aug 13 '13 at 11:11

M. Abbas

score 0 · Answer 5 · answered Aug 13 '13 at 11:18

Since replaceAll uses a regex, you need to escape all the relevant characters ({}\), like this

"something{\\'\\i}".replaceAll("\\{\\\\'\\\\i\\}", "i");

The \\\\ is because you're escaping the \ first in a Java String, then in the regular expression to match a literal \.

score -1 · Answer 6 · answered Aug 13 '13 at 11:21

-1

<script>
    word = "{\'\i}";
    a = word.replace("{"," "");
    a = a.replace("}", "");
    a = a.replace("'", "");

</script>

Just create another rule with the character you want to replace. Not a very good solution but its the most "clean".

answered Aug 13 '13 at 11:21

Tiago

This would replace all sorts of other things, say `{1}`, any other instance of `'`, etc. etc. It's not the most "clean" by any stretch of the imagination, it's just bound to go wrong sooner or later. – Vala Aug 13 '13 at 13:10
this will only replace any characters that he wants. Just create a rule for each one...if the initial string is {1} the output will be 1 and that is what is wanted. Or at least i thought so – Tiago Aug 13 '13 at 13:19
But he doesn't want to remove all of those characters with no other restrictions, he wants to remove those characters if they're around the `i`. Your code will have loads of side effects under certain conditions; consider for example the (arbitrarily chosen) String `"{x} 'hello' {\'\i}"` - your solution results in `"x hello \\i"`, the desired result is `"{x} 'hello' i"`. Note that your solution doesn't even remove the backslashes. – Vala Aug 13 '13 at 14:45

6 Answers6