How do I sort a list of string by part of it in Python?

Question

Here is a list of key from a dictionary:

bandlist = ['B28', 'B26', 'B11', 'B21', 'B20', 'B7', 'B13', 'B3', 'B19', 'B8', 'B1']

sorted(bandlist) == ['B1', 'B11', 'B13', 'B19', 'B20', 'B21', 'B26', 'B28', 'B3', 'B7', 'B8']

But I want it to be arranged in the order of the number after 'B', such as:

['B1', 'B3', 'B7', 'B8', 'B11', 'B13', 'B19', 'B20', 'B21', 'B26', 'B28']

How can I do?

There's also http://stackoverflow.com/questions/4287209/sort-list-of-strings-by-integer-suffix-in-python — lmjohns3, Aug 15 '13 at 04:41

score 2 · Accepted Answer · answered Aug 15 '13 at 04:29

2

Use optional key argument:

>>> bandlist = ['B28', 'B26', 'B11', 'B21', 'B20', 'B7', 'B13', 'B3', 'B19', 'B8', 'B1']
>>> sorted(bandlist, key=lambda x: int(x[1:]))
['B1', 'B3', 'B7', 'B8', 'B11', 'B13', 'B19', 'B20', 'B21', 'B26', 'B28']

answered Aug 15 '13 at 04:29

falsetru

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How do I sort a list of string by part of it in Python?

1 Answers1