Check array for partial match (PHP)

Question

I have an array of filenames which I need to check against a code, for example

array("120_120_435645.jpg","150_150_312312.jpg","250_250_1232327.jpg");

the string is "312312" so it would match "150_150_312312.jpg" as it contains that string. If there are no matches at all within the search then flag the code as missing.

I tried in_array but this seems to any return true if it is an exact match, don't know if array_filter will do it wither...

Thanks for any advice...perhaps I have been staring at it too long and a coffee may help :)

The point is that you don't need a loop by using `preg_grep`. — Jeroen van den Broek, Aug 20 '13 at 15:58

score 16 · Answer 1 · edited May 23 '17 at 12:16

$filenames = array("120_120_435645.jpg","150_150_312312.jpg","250_250_1232327.jpg");
$matches = preg_grep("/312312/", $filenames);
print_r($matches);

Output:

Array
(
    [1] => 150_150_312312.jpg
)

Or, if you don't want to use regex, you can simply use strpos as suggested in this answer:

foreach ($filenames as $filename) {
    if (strpos($filename,'312312') !== false) {
    echo 'True';
    }
}

Demo!

Check array for partial match (PHP)

1 Answers1

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