if (key.equals ("1") || key.equals ("Circle")){
how can i make this statement true even if I enter the string "CiRcle" or "circle"? I mean at different cases.
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13`equalsIgnoreCase`. Look it up in `String` Javadoc. – Marko Topolnik Aug 21 '13 at 12:55
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2@TruGamer equalsIgnoreCase :) – Burak Keceli Aug 21 '13 at 12:56
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3did you try searching for "java string equal case insensitive"? – John Dvorak Aug 21 '13 at 12:56
4 Answers
1
You can try as below :
if (key.equals ("1") || key.equalsIgnoreCase("Circle")){
Butani Vijay
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The general syntax is
public boolean equalsIgnoreCase(String anotherString)
This method returns true if the argument is not null and the Strings are equal, ignoring case; false otherwise.
For your case
if (key.equals("1") || key.equalsIgnoreCase("Circle"))
Vignesh Vino
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You can try
if (key.equals ("1") || key.equalsIgnoreCase ("Circle"))
However it seems like you did not have any research or studied String methods in java. I recommend you to look at String topic in java
Sami
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