jQuery indexof from the second same character

Question

how to get the second same character and index from that second character ?

string example: hello&4&I am searching the second same character

I know how to get first "&".

position = data.indexOf("&");

How to get the second "&" position ? When the 4 number is dynamic ?

Sorry for bad english.

possible duplicate of [Finding the nth occurrence of a character in a string in javascript](http://stackoverflow.com/questions/12744995/finding-the-nth-occurrence-of-a-character-in-a-string-in-javascript) — Felix Kling, Aug 21 '13 at 14:07

score 7 · Accepted Answer · answered Aug 21 '13 at 14:05

7

var data = "hello&4&I";
// offset is the one after the first.
var position = data.indexOf("&", data.indexOf("&") + 1);
console.log(position)
// returns 7

JSBin

Oh, and also... this is vanilla js. You don't need JQuery for this.

answered Aug 21 '13 at 14:05

brbcoding

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score 1 · Answer 2 · edited May 23 '17 at 10:31

1

You can take

position = data.lastIndexOf("&");

Or use a generic function to get the nth position of a string in a string: How to get the nth occurrence in a string?

edited May 23 '17 at 10:31

Community

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answered Aug 21 '13 at 14:04

Spork

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If in the sentence will be character "&" ? What to do then ? – andys Aug 21 '13 at 14:05
See http://stackoverflow.com/questions/14480345/how-to-get-the-nth-occurrence-in-a-string :) – Spork Aug 21 '13 at 14:07

jQuery indexof from the second same character

2 Answers2