I have a text file and I need to read from the seconds line to to 15th line including. I've tried some methods but no method worked for me... I'd be happy if anyone could help me ... thanks a lot!
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4 Answers
42
Use itertools.islice:
from itertools import islice
with open('filename') as fin:
for line in islice(fin, 1, 16):
print line
Jon Clements
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1+1 best way to do this. – Ashwini Chaudhary Aug 24 '13 at 19:15
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@AshwiniChaudhary Why is it the best way? Because `islice` uses generator expressions? – thefourtheye Aug 24 '13 at 19:31
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1@thefourtheye `islice` is a fast and pythonic way to get a slice from an iterator, It does loops over the iterator but that happens internally at C speed. – Ashwini Chaudhary Aug 24 '13 at 19:49
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+1 This seems very elegant. I wasn't aware of `islice` before. `itertools` is quite the treasure chest! – Frerich Raabe Feb 18 '14 at 21:11
9
If the file isn't very big:
with open('/path/to/file') as f:
print f.readlines()[1:15]
4
Jon's answer is definitely a more pythonic and clean approach.
Alternatively, you can use enumerate():
with open("file", 'r') as f:
print [x for i, x in enumerate(f) if 1 <= i <= 15]
Note, that this will loop over all lines in a file. It's better to break the loop after the 15th line, like this:
with open("file", 'r') as f:
for i, x in enumerate(f):
if 1 <= i <= 15:
print x
elif i > 15:
break
4
I think you can just read the lines and take the ones you need
For example:
with open("a.txt", "r") as text_file:
data = text_file.readlines()
now data[1] will be second line and data[14] will be 15th, so you can slice it as such data[1:14]
Then you can put them into a variable and that's it
Ofek .T.
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