if-check for all array values

Question

I have a form in HTML and a code in PHP. The form contains a lot of different <input> things. And I want some text to output in a browser only if all the fields are not empty.

For example, for two fields called name and age, I would do the following:

if($_POST['name'] and $_POST['age']) { ... }

But here I have much more than two fields. What should I do?

[**This could help**](http://stackoverflow.com/a/3190482/1415724) — Funk Forty Niner, Aug 26 '13 at 14:00

score 6 · Accepted Answer · answered Aug 26 '13 at 13:43

6

You could try something like this

$allSet = true;
foreach($_POST as $key => $value){
    if(empty($value)){
        $allSet = false;
        break;
    }
}

answered Aug 26 '13 at 13:43

Dragony

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I like the method, but doesn't give the specific error message to what has been left blank. Also you should move this into a function + trim the value before verifying if it's empty – Daryl Gill Aug 26 '13 at 13:45
Sure, there is a lot that could be done. The goal is to point him in the right direction :) – Dragony Aug 26 '13 at 13:45

Brewal · Answer 2 · 2013-08-26T14:07:33.630

2

You can also try this if all inputs sent are required :

if (count(array_filter($_POST)) != count($_POST)) {
    // at least one input is empty
}

See array_filter()

This function returns the same array, without the values that are null, false, 0 or empty string. So if there is less entries in the filtered array than in the original, this means that at least one input has not been filled.

Edit : And it works !

edited Aug 26 '13 at 14:07

answered Aug 26 '13 at 13:47

Brewal

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I like the solution, it's pretty slick, but it's probably not something that is on the right level for the guy that asked the question. – Dragony Aug 26 '13 at 13:54
@Dragony Yeah, I like to make it simple and short. Maybe that's not on the "right level" of the down voters neither ! Still, it could be useful for anyone understands it :) – Brewal Aug 26 '13 at 13:58
Actually, this one is a lot more simple and doesn't need an array of POST variables. – Funk Forty Niner Aug 26 '13 at 14:27

score 1 · Answer 3 · answered Aug 26 '13 at 13:45

1

Simple function. You can append required fields array('name', 'age', 'phone')

function checkPost()
{
    if (!$_POST) return false;

    $fields = array('name', 'age');
    foreach ($fields as $field)
    {
        if(!$_POST[$field])
            return false;
    }
    return true;
}

if(checkPost()) { ... }

answered Aug 26 '13 at 13:45

Bora

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5
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The structure seems a tad too complex for what it looks, the OPS Skill level – Daryl Gill Aug 26 '13 at 13:47
No complex. Just require push new fields to array. – Bora Aug 26 '13 at 13:48

if-check for all array values

3 Answers3