Add minutes to datetime string

Question

$datetime_from = '2013-08-27 14:17:00';
$datetime_till = date("Y-m-d H:i",strtotime("+45 minutes",$datetime_from));

The result is:

$datetime_till = '1970-01-01 01:00:00'

The expected result is

$datetime_till = '2013-08-27 15:02'

How to get it?

http://stackoverflow.com/questions/8169139/adding-minutes-to-date-time-in-php — Matt, Aug 27 '13 at 12:50

GautamD31 · Answer 1 · 2013-08-27T13:00:39.753

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It will be like

$datetime_from = strtotime('2013-08-27 14:17:00');
$datetime_till = date("Y-m-d H:i",strtotime("+45 minutes",$datetime_from));

You need to convert $datetime_from to time

Orelse you can also try like(Iam not sure)

$dateTime = DateTime::createFromFormat('m/d/Y h:i', $datetime_from);
$datetime_from = $dateTime->format('U');
$datetime_till = date("Y-m-d H:i",strtotime("+45 minutes",$datetime_from));

edited Aug 27 '13 at 13:00

answered Aug 27 '13 at 12:50

GautamD31

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It provides the same answer: 1970-01-01 01:45:00 – Klausos Klausos Aug 27 '13 at 12:53
Probably the problem is that var_dump($datetime_from); outputs "'2013-08-27 17:00:00'" – Klausos Klausos Aug 27 '13 at 13:11
If you are using `DateTime` classes, don't mix them with old `date()` or `strtotime()` functions. – Glavić Aug 27 '13 at 13:31
What is the reason to down it..?? – GautamD31 Sep 07 '13 at 07:34

score 0 · Answer 2 · answered Aug 27 '13 at 12:52

0

Try-

$datetime_till = date("Y-m-d H:i",strtotime("+45 minutes",strtotime($datetime_from)));

answered Aug 27 '13 at 12:52

Sahil Mittal

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score 0 · Answer 3 · answered Aug 27 '13 at 12:56

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You should use the DateTime class instead of old functional php.

$dateFrom = new \DateTime('2013-08-27 14:17:00');
$dateTill = new \DateTime('2013-08-27 14:17:00');
$dateTill->modify('+45 minutes');

// test if the dates are correct
echo $dateFrom->format('Y-m-d H:i:s'). ' - '.$dateTill->format('Y-m-d H:i:s');

There are numerous other methods you can benefit from the DateTime class.

answered Aug 27 '13 at 12:56

Laurynas Mališauskas

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This line fails: $datetime_till = new DateTime($datetime_from); – Klausos Klausos Aug 27 '13 at 13:12
Probably the problem is that var_dump($datetime_from); outputs "'2013-08-27 17:00:00'". But how to fix it? – Klausos Klausos Aug 27 '13 at 13:12
add a backslash before DateTime. $datetime_from must be a string with a valid format date. – Laurynas Mališauskas Aug 27 '13 at 13:42

score 0 · Answer 4 · answered Aug 27 '13 at 13:04

You can use the DateTime object to do this in procedural style PHP like this:

$datetime_from = date_create('2013-08-27 14:17:00'); // Create a date object from the start date
$datetime_till = date_add($datetime_from, date_interval_create_from_date_string('45 minutes')); // Add the interval to the starting time
echo date_format($datetime_till, 'Y-m-d H:i'); // Format the date how you want it to be output

Hope this helps.

score 0 · Answer 5 · answered Aug 27 '13 at 13:09

0

Use:

$datetime_from = strtotime('2013-08-27 14:17:00');

$datetime_till = date("Y-m-d H:i",$datetime_from+(45*60));

answered Aug 27 '13 at 13:09

Yatin Trivedi

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Glavić · Answer 6 · 2013-08-27T13:38:35.630

Use DateTime class for date/time modifications :

$datetime_from = new DateTime('2013-08-27 14:17:00');
$datetime_till = clone $datetime_from;
$datetime_till->modify('+45 minutes');

echo
    'From: ' . $datetime_from->format('Y-m-d H:i:s') . "\n".
    'Till: ' . $datetime_till->format('Y-m-d H:i:s');

Output will be :

From: 2013-08-27 14:17:00
Till: 2013-08-27 15:02:00

Valid modify() formats are explained in Date and Time Formats.

_{Please note that various strtotime() examples are not correct in date/time difference calculation. The simplest example is difference between 2013-03-31 21:00 and 2013-03-30 21:00. Which for naked eye is exact 1 day difference, but if you do subtract this 2 dates, you will get 82800 seconds which is 0.95833333333333 days. This is because of the time change from winter to summer time. DateTime handles leap years and time-zones properly.}

Add minutes to datetime string

6 Answers6