How to convert php array variable to javascript variable

Question

Here is my code which is retrieving from db... and i stored that column values in array() variable...

$res1 = array();
while ($row = mysql_fetch_assoc($res)) {
    $res1[$i] = $row['address'];
    $i = $i + 1;
}

print_r($res1);

But problem is wen am trying to print this array it is printing as below:

"Array ( [0] => ameerpet [1] => panjagutta )"

but i need to print that array as below so that i can store in js variable for further using......

["ameerpet", "panjagutta"];

json_encode will help you. – 웃웃웃웃웃 Aug 28 '13 at 10:01 — 웃웃웃웃웃, Aug 28 '13 at 10:01
Search function!! Usage is **not optional** – Gordon Aug 28 '13 at 10:12 — Gordon, Aug 28 '13 at 10:12

score 1 · Accepted Answer · answered Aug 28 '13 at 10:04

1

Use json_encode() to encode your array to JSON format:

$json = json_encode($res1);

You can use that variable in JavaScript and use then use JSON.parse():

json = <?php echo $json; ?>
var obj = JSON.parse(json);
// obj now contains the array

answered Aug 28 '13 at 10:04

Amal Murali

it is working but no need of json.parse....because if i use json.parse it is not accepting but wen i use direct var obj= it is accepting... – Sweety Mouni Aug 28 '13 at 10:32

score 0 · Answer 2 · answered Aug 28 '13 at 10:04

0

Add this line where you want to declare the js array variable.

echo "var js_array = ". json_encode($res1) . ";\n";

answered Aug 28 '13 at 10:04

rgin

2 Answers2