Get all last descendants of a base type?

Question

This question is an opposite of How to find types that are direct descendants of a base class?

If this is the inheritance hierarchy I have,

class Base
{

}



class Derived1 : Base
{

}

class Derived1A : Derived1
{

}

class Derived1B : Derived1
{

}



class Derived2 : Base
{

}

I need a mechanism to find all the sub types of Base class in a particular assembly which are at the end of the inheritance tree. In other words,

SubTypesOf(typeof(Base))

should give me

-> { Derived1A, Derived1B, Derived2 }

score 2 · Accepted Answer · edited May 23 '17 at 12:32

2

This is what I have come up with. Not sure if some more elegant/efficient solutions exist..

public static IEnumerable<Type> GetLastDescendants(this Type t)
{
    if (!t.IsClass)
        throw new Exception(t + " is not a class");

    var subTypes = t.Assembly.GetTypes().Where(x => x.IsSubclassOf(t)).ToArray();
    return subTypes.Where(x => subTypes.All(y => y.BaseType != x));
}

And for sake of completeness, I will repost the answer for direct descendants given here

public static IEnumerable<Type> GetDirectDescendants(this Type t)
{
    if (!t.IsClass)
        throw new Exception(t + " is not a class");

    return t.Assembly.GetTypes().Where(x => x.BaseType == t);
}

edited May 23 '17 at 12:32

Community

1
1

answered Aug 28 '13 at 12:27

nawfal

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What about Derived1 ? – I4V Aug 28 '13 at 12:33
@I4V Derived1 is not at the end of the hierarchy tree. It has children. I had a special requirement today where I wanted the youngest lot :) – nawfal Aug 28 '13 at 12:35

Get all last descendants of a base type?

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