Neither $
or @
are part of standard C's character set (C11 5.2.1 Character sets, paragraph 3):
Both the basic source and basic execution character sets shall have the following members: the 26 uppercase letters of the Latin alphabet
A B C D E F G H I J K L M
N O P Q R S T U V W X Y Z
the 26 lowercase letters of the Latin alphabet
a b c d e f g h i j k l m
n o p q r s t u v w x y z
the 10 decimal digits
0 1 2 3 4 5 6 7 8 9
the following 29 graphic characters
! " # % & ' ( ) * + , - . / :
; < = > ? [ \ ] ^ _ { | } ~
the space character, and control characters representing horizontal tab, vertical tab, and form feed.
The C++ standard says about the same (2.2 Character sets, paragraph 1):
The basic source character set consists of 96 characters: the space character, the control characters representing horizontal tab, vertical tab, form feed, and new-line, plus the following 91 graphical characters:
a b c d e f g h i j k l m n o p q r s t u v w x y z
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
0 1 2 3 4 5 6 7 8 9
_ { } [ ] # ( ) < > % : ; . ? * + - / ^ & | ∼ ! = , \ " ’
So if you can or can't use them (at all or even for a specific purpose) it's up to your implementation.
In your case it sounds like you're probably using GCC, which allows $
in identifiers as an extension, but doesn't allow @
- probably because GCC also compiles Objective-C code, where @
has special meaning.
From the GCC documentation:
In GNU C, you may normally use dollar signs in identifier names. This is because many traditional C implementations allow such identifiers. However, dollar signs in identifiers are not supported on a few target machines, typically because the target assembler does not allow them.