how return value to ajax call

Asked Aug 29 '13 at 08:25

Active Aug 29 '13 at 08:25

Viewed 74 times

I have a code here that successfully alerts "Success" from the echo of submit.php.

var result = $.ajax({
             type: "POST",
             url: "ajax/submit.php",
             datatype: "html",
             data: "&data="+$_employmentBackground,
             async: false
            }).responseText;

alert(result);

but when I put if statement around, it is not working anymore..

if(result == "Success")
{
   alert(result);
}

Do you have any idea why is it not working?

asked Aug 29 '13 at 08:25

QKWS

1,069
9
22
41

1

check `typeof result` – karaxuna Aug 29 '13 at 08:27
type of result? what should it be? – QKWS Aug 29 '13 at 08:28
4

Why `async:false`? Just do the logic inside the callback... – elclanrs Aug 29 '13 at 08:28
2

I suppose you're sending some trailing spaces to the response, this would explain why the condition is false – Fabrizio Calderan Aug 29 '13 at 08:28
`alert(typeof result)` it should be string – karaxuna Aug 29 '13 at 08:28
First of all read the documentation http://api.jquery.com/jQuery.ajax/ – Alexander Larikov Aug 29 '13 at 08:28
You can use FireBug and put a breakpoint on if, then check what kind of object `result` is. – ksalk Aug 29 '13 at 08:29
1

Fabrizio may be right, try it like this: `if(result.trim() == "Success")` – karaxuna Aug 29 '13 at 08:29
Refer to the Ajax 101 guide at http://fixingthesejquery.com/images/ajax101.png and the marvellous http://fixingthesejquery.com/#slide33 – xec Aug 29 '13 at 08:30
`dataType: 'json'` then in PHP `echo json_encode('Success')` – elclanrs Aug 29 '13 at 08:30
THANKS FOR ALL THE COMMENT @FabrizioCalderan is right, its because of the spaces.. :) – QKWS Aug 29 '13 at 08:33
@QKWS so answer to your own question and mark it as accepted (I'm not looking for easy rep) – Fabrizio Calderan Aug 29 '13 at 08:34

how return value to ajax call

0 Answers0