Find the index of the second occurrence of a string inside a list

Question

This is my list and code:

x=[["hi hello"], ["this is other"],["this"],["something"],["this"],["last element"]]
for line in x:
    y=x.index(line)
    #code

The first time it gets "this", it works properly, but for the second time, it gets the index of the first "this" only!

How can I find the second occurrence of a string inside a list?

What you are trying to do exactly? Seems like you are storing a single string in a list and that seems unnecessary — Joohwan, Sep 03 '13 at 05:05
actually, i'm reading a file, and store in a list called x! i just gav simple example!! — no1, Sep 03 '13 at 05:15
Try checking out my answer I think I know what you are trying to do — Joohwan, Sep 03 '13 at 05:34
No! its complicated! Anyhow i got the answer, thank you...:) — no1, Sep 03 '13 at 05:49

score 5 · Accepted Answer · answered Sep 03 '13 at 05:06

5

You could use enumerate(...) here.

>>> x=[["hi hello"], ["this is other"],["this"],["something"],["this"],["last element"]]
>>> for index, line in enumerate(x):
        print index, line


0 ['hi hello']
1 ['this is other']
2 ['this']
3 ['something']
4 ['this']
5 ['last element']

answered Sep 03 '13 at 05:06

Sukrit Kalra

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Glad this helped you out. :) – Sukrit Kalra Sep 03 '13 at 05:28
ya...used your solution, and its working for me... thankx again! – no1 Sep 03 '13 at 05:48

score 4 · Answer 2 · edited May 23 '17 at 12:01

You can get the second easily enough by using list slices. In the example below, we find the index of the first occurance and then find the index of the first occurance in the sub-list that begins just after the first occurance.

x=[["hi hello"], ["this is other"],["this"],["something"],["this"],["last element"]]
for line in x:
    first=x.index(line)
    second=x[first+1:].index(line)
    #code

Bare in mind that using list.index() will return a ValueError if the object isn't in the list. Thus you may want some exception handling around your inner loop.

So the final code will look somewhat closer to this:

x=[["hi hello"], ["this is other"],["this"],["something"],["this"],["last element"]]
for line in x:
    print lines
    try:
        first=x.index(line)
        second=x[first+1:].index(line)
    except:
        first,second=-1,-1
    print first,second
    #code

Joohwan · Answer 3 · 2013-09-03T05:39:20.010

If getting the indices of the keyword is the only thing you need to do, then storing strings in a list is unnecessary (even if this was just an example you thought of!).

This function would print out each line and all the indices of the keyword (if any) that you give found per line in the file:

def getIndices(keyword):

    f = open('pathToYourFile', 'r')
    for line in f:

        wordList = line.split()
        buf = line.strip("\n") + ": "

        i = 0
        while i < len(wordList):
            if wordList[i] == keyword:
                buf += str(i) + " "
            i += 1

        print buf

This way you won't be limited to the keyword "this" and 1st/2nd occurrences. For example, let's say your file looked like this:

hello this
this is cool
hello there
this this this

Then the function will work like this:

>>> getIndices("this")
hello this: 1 
this is cool: 0 
hello there: 
this this this: 0 1 2

Find the index of the second occurrence of a string inside a list

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