How apply an alphabetical function on a var?

Question

How i can sum up these var ?

var curb = $("#nav-b").position().top;
var curc = $("#nav-c").position().top;
var curd = $("#nav-d").position().top;
var cure = $("#nav-e").position().top;
var curf = $("#nav-f").position().top;
var curg = $("#nav-g").position().top;
var curi = $("#nav-i").position().top;

I have tried something using this:

var let = '';
var charCodeRange = {
    start: 66,
    end: 90
} // b to z
for (var cc = charCodeRange.start; cc <= charCodeRange.end; cc++) {
    let = String.fromCharCode(cc);
    'cur' + let = $("#nav-" + let).position().top;
}

Why not push all the values into an array and add them that way? — Evan Davis, Sep 04 '13 at 16:33
use a class name instead and you can select all those elements in one call. — Ibu, Sep 04 '13 at 16:36
Assuming your problem is `cur + let = ...`, this is probably a duplicate of [Dynamic Javascript variable names](http://stackoverflow.com/questions/7762502/dynamic-javascript-variable-names) — apsillers, Sep 04 '13 at 16:40

score 2 · Answer 1 · answered Sep 04 '13 at 16:41

2

Why aren't you using classnames? You can just put the class of "letter" on the ones you need. Here's a quick example.

var total = 0;

$('.letter').each(function(){
  total += $(this).position().top;
});

answered Sep 04 '13 at 16:41

Bill Criswell

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I use them in functions after: if($("#nav-b").position().top < 20 && $("#nav-b").position().top > -20) { if(curb < $("#nav-b").position().top) changeNavIndicator("A"); else changeNavIndicator("B");; curb = $("#nav-b").position().top; } – zorg Sep 04 '13 at 16:48

How apply an alphabetical function on a var?

1 Answers1