The right way to allocate the memory would be something like
size_t elements = 0;
... // get the number of elements as a separate operation
pixel *buffer = malloc( sizeof *buffer * elements ); // note no cast,
// operand of sizeof
if ( buffer )
{
// load your buffer here
}
In C, casting the result of malloc
is considered bad practice1. It's unnecessary, since values of void *
can be assigned to any pointer type, and under C89 compilers it can suppress a diagnostic if you forget to include stdlib.h
or otherwise don't have a declaration for malloc
in scope.
Also, since the expression *buffer
has type pixel
, the expression sizeof *buffer
is equivalent to sizeof (pixel)
. This can save you some maintenance time if the type of buffer
ever changes.
How you get the number of elements for your array really depends on your application. The easiest way would be to stick that value at the head of your data file:
size_t elements = 0;
FILE *data = fopen( "pixels.dat", "r" );
if ( !data )
{
// You will want to add real error handling here.
exit( 0 );
}
if ( fscanf( data, "%zu", &elements ) != 1 )
{
// You will want to add real error handling here
exit( 0 );
}
pixel *buffer = malloc( sizeof *buffer * elements );
if ( buffer )
{
for ( size_t i = 0; i < elements; i++ )
{
if ( fscanf( data, "%hhu %hhu %hhu", // %hhu for unsigned char
&buffer[i].r, &buffer[i].g, &buffer[i].b ) != 3 )
{
// more real error handling here
exit( 0 );
}
}
}
Naturally, this assumes that your data file is structured as rows of 3 integer values, like
10 20 30
40 50 60
etc.
1. As opposed to C++, where it's required, but if you're writing C++ you should be using the new
operator anyway. Yes, you will see thousands of examples that include the cast. You will also see thousands of examples that use void main()
. Most C references are simply crap.