$array1 = array(1,1,1);
$array2= array(1,5,9,2,2,1);
I need to compare $array2
with $array1
and if $array2
has the same identical values should return true
, otherwise should be returning false. In this case it should return false
$array1 = array(1,1,1);
$array2= array(1,5,9,2,2,1);
I need to compare $array2
with $array1
and if $array2
has the same identical values should return true
, otherwise should be returning false. In this case it should return false
You can use the ==
and ===
operators.
$array1 == $array2
only checks if the two arrays contain the same key/value pairs and $array1 === $array2
also checks if they are in the same order and if they are of the same type.
See the PHP manual.
if ( $array1 == $array2 ) {
return true;
}
else{
return false;
}
Note: keys must be same too.
To check only values:
if(!array_diff($array1, $array2) && !array_diff($array2, $array1))
return true;
Well thanks @Shadowfax for trying help but i made the solution, so i post here if anyone have the same problem..
function compareArrayValues($array1,$array2){
$result= array();
for ($a=0; $a< count($array1); $a++){
$array2=array_values($array2);
for ($b=0; $b < count($array2) ; $b++) {
if ($array1[$a] == $array2[$b]){
array_push($result,$array1[$a]);
unset($array2[$b]);
break;
}
}
}
if ($result == $array1){
return true;
}else{
return false;
}
}