PHP Data- URI to Image

Question

I have Data URI(image) and I am trying to save using php, my code is

$filename = 'test.png';
$fp = fopen("user_images/".$filename,"w");
fwrite($fp, base64_decode($_POST['strDataURI']));
fclose($fp);

It gives me corrupted image always, But i am getting right image when i use in Javascript

document.write('<img src="'+strDataURI+'"/>');

data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAoAAAAHgCAYAAAA10dzkAAAEvklEQVR4nO3BAQ0AAADCoPdPbQ43oAAAA — Nithin Dev, Sep 10 '13 at 12:26
(I'd probably just try this: `fwrite($fp, file_get_contents($_POST['strDataURI']);`; think it should work in recent versions of PHP, which can handle data URIs without the double-slash.) — Matt Gibson, Sep 10 '13 at 12:35
because data uris have a prefix with the mime type ,you need to remove it before decoding the base 64 string. — mpm, Sep 10 '13 at 12:41

score 2 · Accepted Answer · edited Feb 16 '15 at 23:28

2

Given that I believe PHP now supports (>5.4.17 ) "proper" data URIs (i.e. without the double-slash necessary in older versions) I'd probably just try this:

fwrite($fp, file_get_contents($_POST['strDataURI']);

...seems to work okay in PHP 5.4.17 using a test script I just wrote using a data uri generated from this online tool.

edited Feb 16 '15 at 23:28

Toby Allen

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answered Sep 10 '13 at 12:42

Matt Gibson

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PHP Data- URI to Image

1 Answers1