Getting list out of python list of list

Question

I am using a list of list as follows:

L = [['a', 4], ['b', 2], ['c', 13]]

I want to generate a new list for all the numbers which are in the second position in each set of the list:

L =  [4, 2, 13]

Is there any shortcut in python to get the above list?

yeah, two possible ways to do the same thing, i was unaware of zip, so couldn't find it earlier — Pradeep, Sep 11 '13 at 10:28
@pradeep [Here's a link to the documentation on `zip()`](http://docs.python.org/2/library/functions.html#zip) — TerryA, Sep 11 '13 at 10:30

score 6 · Accepted Answer · answered Sep 11 '13 at 10:20

6

Use a list comprehension:

>>> L = [['a', 4], ['b', 2], ['c', 13]]
>>> print [i[1] for i in L]
[4, 2, 13]

This accesses the second item in each list (remember that indexing starts at zero, so 1 gets the second index)

answered Sep 11 '13 at 10:20

TerryA

Can I assign it to new List ? – Pradeep Sep 11 '13 at 10:24
1

@pradeep Yes! Just do `new_list = [i[1] for i in L]` or something like that – TerryA Sep 11 '13 at 10:25

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