Ounces to Stones, lbs and ounces in python

Question

Basically I have been given homework from college and the user has to input an x amount of ounces and it all gets converted and printed out to the screen in Stones, lbs and remaining ounces. I have been stuck on this for nearly a week. Here is the code I've managed to do so far:

inp = int(input("Enter your weight in ounces: "))

stones = int(inp / 224)
inp1 = int(inp - (stones * 14))
pounds = int(inp1 % 16)

print(stones ,"Stones", pounds, "Pounds")

The stones bit works perfectly but I am wondering how you get the remaining ounces and convert them into lbs then the remaining in ounces?

You need to think carefully about the data types. What happens when you divide an int by another int? Also, take care about coercing the result to be a specific type (that is not necessarily what you want). Remember, python is [dynamically but strongly typed](http://stackoverflow.com/questions/11328920/is-python-strongly-typed). — Henry Gomersall, Sep 11 '13 at 13:40

Ankur Ankan · Answer 1 · 2013-09-11T15:38:11.087

The better way would be to convert the ounces into pounds first and then convert the pounds into stones.

def convert(total_ounces):
    ounces = total_ounces % 16
    total_pounds = total_ounces//16      # 1 pound = 16 ounces
    pounds = total_pounds % 14
    stones = total_pounds//14            # 1 stone = 14 pounds
    print stones, " stones ", pounds, "pounds", ounces, " ounces"


>>> convert (110)
    0  stones  6 pounds 14  ounces

>>> convert (500)
    2  stones  3 pounds 4  ounces

And the problems with your code:

inp = int(input("Enter your weight in ounces: "))

stones = int(inp / 224)                    # Here you get the maximum no of stones. You 
                                           # should better be using inp // 224 rather 
                                           # that int(inp / 224).
inp1 = int(inp - (stones * 14))            # Firstly, since both inp and stones*14 would      
                                           # be int so there is no need for using int(). 
                                           # and what I think you are trying to do here  
                                           # is finding the remaining no of ounces, so 
                                           # you should be doing something like
                                           # inp1 = inp - stones * 14 * 16
pounds = int(inp1 % 16)                    # again here there is no need of using int. 
                                           # And inp1 % 16 should return the number of 
                                           # ounces not pounds. Pounds should be inp1 // 16 .


print(stones ,"Stones", pounds, "Pounds")

Thank you so much!! I edited it a little bit to my need but it works! It took me over a week to get this. Thank you very much! — KrisBox, Sep 11 '13 at 14:16
Though I realise the temptation to get the easy upvotes, is telling the OP the answer really the best way to teach them where their problems lie? I suspect that they still haven't really understood why their solution didn't work. — Henry Gomersall, Sep 11 '13 at 15:29
I've downvoted the answer, not because it is wrong, but because it's a poor answer given the question, which is about learning how to program in python. — Henry Gomersall, Sep 11 '13 at 15:29

dawg · Answer 2 · 2013-09-11T21:35:33.777

You are close with yours. This works:

inp = float(input("Enter your weight in ounces: "))

stones = inp / 224
pounds = stones * 14

print('{:.2f} Ounces is {:.2f} Stones or {:.2f} Pounds'.format(inp, stones, pounds))

However, since stone are traditionally expressed with rational numbers, not decimals, you can use the Fractions module in the standard Python library:

import fractions

inp = int(input("Enter your weight in ounces: "))

if inp>=14*16:
    stones, f=inp // 224, fractions.Fraction(inp%224, inp)
    pounds, oz = inp // 16, inp%16
    outs=str(stones)
    if abs(f)>.01:
        outs+=' and {}/{}'.format(f.numerator, f.denominator)

    outs+=' Stone'   
    outs+=' or {} Pounds'.format(pounds)
    if oz>=1:
        outs+=' {} ounces'.format(oz)    
    print(outs)

else:
    f=fractions.Fraction(inp, 224)
    pounds, oz = inp // 16, inp%16

    print('{}/{} Stone or {} Pounds {} ounces'.format(
          f.numerator, f.denominator, pounds, oz))

Example input, output:

Enter your weight in ounces: 1622
7 and 27/811 Stone or 101 Pounds 6 ounces

Enter your weight in ounces: 17
17/224 Stone or 1 Pounds 1 ounces

Enter your weight in ounces: 2240
10 Stone or 140 Pounds

Enter your weight in ounces: 3450
15 and 3/115 Stone or 215 Pounds 10 ounces

Or you can do the traditional British way to print Stone weight by N Stone XX (pounds):

inp = int(input("Enter your weight in ounces: "))
print('{} Stone {}'.format(inp//224, inp%224//16))

Which prints:

Enter your weight in ounces: 2528
11 Stone 4

Ounces to Stones, lbs and ounces in python

2 Answers2