Regex and Javascript pattern build

Question

I just really need help with building a regex of this pattern XXX@XXX.XXX

Starts with at least 3 char not @
then @ (only one)
at least 3 char that are not . or @
and than one .
than 3 char that are not . or @

This is what I played with but it doesnt work

/^([a-zA-Z0-9._-]{3,})\.@([a-zA-Z0-9.-]{3,*})\.[a-zA-Z]{3,*}$/

What characters are legal? Are you trying to match an email address? You might try searching first, as there are hundreds of questions like this. — crush, Sep 13 '13 at 19:53
and if that's for validating email addresses, I can 99% guarantee that none of the answers are correct — Alnitak, Sep 13 '13 at 19:55
At least keep your bad regex consistent! You put `{3,}` which is correct, but then later you put `{3,*}` twice... — Niet the Dark Absol, Sep 13 '13 at 19:55
How does it not work? The regular expression you described is `/[^@]{3,}@[^@.]{3,}\.[^@.]{3}/` — FrankieTheKneeMan, Sep 13 '13 at 19:55
possible duplicate of [Using a regular expression to validate an email address](http://stackoverflow.com/questions/201323/using-a-regular-expression-to-validate-an-email-address) — Jonathan, Sep 13 '13 at 19:55

Adam Wolski · Accepted Answer · 2013-09-13T20:12:48.233

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^[^@]{3,}@[^@\.]{3,}\.[^@\.]{3}$

This is the regex you're looking for. But if you want to validate an e-mail address don't use this regex.

edited Sep 13 '13 at 20:12

answered Sep 13 '13 at 19:55

Adam Wolski

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This is the regex he described, but I think it is very unlikely it is the one he is looking for. – Andrew Clark Sep 13 '13 at 19:56
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true ;-) Validating e-mail with this regex is not proper – Adam Wolski Sep 13 '13 at 19:59
@AdamWolski, You are missing the `^...$`, otherwise we could have `/[^@]{3,}@[^@\.]{3,}\.[^@\.]{3}/.test('@invalid@test.com'); //true` – plalx Sep 13 '13 at 20:06
According to his description, this can be valid. Note, that he didn't say that it should validate an e-mail address. – Adam Wolski Sep 13 '13 at 20:11
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But, according to his attempt (he used ^ and $) you're right ;) – Adam Wolski Sep 13 '13 at 20:12
@AdamWolski, FYI: you don't need to escape `.` when it is in a set. – Daniel Gimenez Sep 13 '13 at 20:28

davide · Answer 2 · 2013-09-13T20:01:30.257

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Try with

 /\b[^@]{3,}@[^.@]{3,}\.[^.@]{3}\b/

it should work. The \b means a token boundary.

edited Sep 13 '13 at 20:01

answered Sep 13 '13 at 19:55

davide

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score 0 · Answer 3 · answered Sep 13 '13 at 19:58

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/^([^@]{3,})@([^.@]{3,})\.([^.@]{})$/

First block matches atleast 3 characters that are not @ Second is one @ Third is atleast 3 characters that are not . or @ Fourth is a . Fifth is 3 characters that are not . or @

answered Sep 13 '13 at 19:58

Cjmarkham

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Regex and Javascript pattern build

3 Answers3