Extracting the terms of a String using regex in java

Question

Sorry for the bad title, but really could not find some other words for it. But, I am working in java and i have the following pattern matching to do.

The pattern is (\\w)*(\\s+)(\\w)*(\\,)(\\s*)(\\w)*(\\,)?(\\s*)(\\w)*

The String to be matched is of the type "add r0, r1, r2". Now, how can I extract the all the individual strings from the above string, ie. add,r0,r1 and r2? To make it clearer, if the input string were "mov r1, r4", I would like to extract mov, r1 and r4. How to go about this?

possible duplicate of [Using Regular Expressions to Extract a Value in Java](http://stackoverflow.com/questions/237061/using-regular-expressions-to-extract-a-value-in-java) — Narendra Pathai, Sep 14 '13 at 12:55

score 0 · Answer 1 · answered Sep 14 '13 at 12:55

0

Hint: Don't try to match the full string using a complex regex and use String#split(regex) to split it using space or comma i.e. "[, ]" and get your tokens from resulting array.

String input = "add r0, r1, r2";
String[] arr = input.split("[ ,]+"));
// [add, r0, r1, r2]

answered Sep 14 '13 at 12:55

anubhava

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I would like to avoid splitting. Is there anyway I can directly access the terms, like in Ocaml? – alpha42 Sep 14 '13 at 12:57
What would be good reason to avoid split call and make it more complicated to solve? – anubhava Sep 14 '13 at 12:59
I was wondering if there was any other direct access method. If it is not, then I guess split is the only option? – alpha42 Sep 14 '13 at 13:02
split is definitely the simplest. – anubhava Sep 14 '13 at 13:05

score 0 · Accepted Answer · answered Sep 14 '13 at 12:56

0

You can try this:-

String yourinput="add r0, r1, r2"
String[] s=yourinput.split("[\\s,]+");

answered Sep 14 '13 at 12:56

Rahul Tripathi

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Extracting the terms of a String using regex in java

2 Answers2