Can I create a ranked dict by iterating over an existing dict?

Question

I've been searching for the answer to this for a while, but no joy.

I have a dict containing hotel names and prices.

mydict = {'HotelA': 100, 'HotelB': 300, 'HotelC': 200}

I would simply like to iterate over the dict and return a separate dict whose values rank the keys based on lowest to highest values, eg:

mynewdict = {'HotelA': 1, 'HotelB': 3, 'HotelC': 2}

I am aware of how to use sorted to iterate over a dictionary and provide an ordered list, but am unsure as to the best way to handle the above. All help greatly appreciated.

I'm pretty new to Python and haven't found anything I CAN try yet, hence coming here and explaining exactly what I want to do in explicit terms. — user2781522, Sep 15 '13 at 16:12
have a look at http://stackoverflow.com/questions/613183/python-sort-a-dictionary-by-value and the builtin `enumerate` function — , Sep 15 '13 at 17:16

score 0 · Answer 1 · answered Sep 16 '13 at 15:23

>>>import operator
>>>mydict = {'HotelA': 100, 'HotelB': 300, 'HotelC': 200}
#Sorting a list of tuples based on their second element (the value ex.: 100, 200, 300)
>>>sorted_list = sorted(mydict.iteritems(), key=operator.itemgetter(1))

In that case sorted_list will be an ordered list of tuples, each tuples containing the name of the hotel and the value:

[('HotelA', 100), ('HotelC', 200), ('HotelB', 300)]

Can I create a ranked dict by iterating over an existing dict?

1 Answers1