9

As you might have seen in the title, my programming background is Java. In Java you can do stuff like this

new Object().callSomeMethod();

without assigning the created Object to a variable, very useful and clear coding if you only need this Object once.

Now in PHP i try to do the same

new Object()->callSomeMethod();

but here i get a 'Parse error: syntax error, unexpected '->' (T_OBJECT_OPERATOR)'.

Is there a way to do this in PHP ?

Basti Funck
  • 1,400
  • 17
  • 31

1 Answers1

18
(new Object())->callSomeMethod();

will work in PHP 5.4+

EDIT

It is a new feature added on PHP 5.4:

Class member access on instantiation has been added, e.g. (new Foo)->bar().

EDIT2

The PHP feature RFC proposes two sets of syntax(with & without brackets), both of them are implemented in the RFC, but only one has been shipped. I couldn't find links explaining the decision.

Let's take a look at the bracketless syntax examples in the RFC:

  • new foo->bar() should be read as (new foo)->bar()
  • new $foo()->bar should be read as (new $foo())->bar
  • new $bar->y()->x should be read as (new ($bar->y)())->x

I think bracketless syntax is not shipped because its proposed parsing precedence is not very intuitive(hard to follow by eyes) as shown in the 3rd example.

Kita
  • 2,604
  • 19
  • 25
  • 2
    Why does PHP not allow the syntax as mentioned by OP? – Jon Koops Jan 12 '14 at 05:14
  • Can you include information about why the parentheses are neccessary? According to the operator precedence list, `new` has highest precedence, but `->` occurs nowhere in this list... – Jasper Feb 12 '15 at 13:38
  • Thanks, but this doesn't address my question why the parens are neccessary. – Jasper Feb 13 '15 at 12:31