Regex for a decimal number

Question

I used the following regex

var x=32423332.343;
var res= x.toString().replace(/\B(?=(\d{3})+(?!\d))/g, ",");

which gives an output of 32,423,332.343

How do I modify this regex (shortest way) to get the following output

3,24,23,332.343

Are you sure you want such a format!? I've never seen that before. — Jerry, Sep 18 '13 at 16:40
@Jerry: http://en.wikipedia.org/wiki/Indian_Numbering_System — Tim Pietzcker, Sep 18 '13 at 16:41
@TimPietzcker that format is the most common format used, so you will find it everywhere :) — user1814374, Sep 18 '13 at 16:46

Jerry · Accepted Answer · 2013-09-18T17:54:13.163

1

Well, if you want that, you can modify your regex a bit:

\B(?=(?:\d{2})*\d{3}(?!\d))

(?:\d{2})* will match even number of digits before the final \d{3}.

For PCRE engine, one that can handle integers and floating, with g enabled.

\G\d{1,2}\K\B(?=(?:\d{2})*\d{3}(?!\d))

edited Sep 18 '13 at 17:54

answered Sep 18 '13 at 16:44

Jerry

1

@user1814374 You're welcome! Thanks to you, I learned something new today as well ;) – Jerry Sep 18 '13 at 17:05

1 Answers1