What does the following code do in php?

Question

Please explain the following code. I can't understand what is happening.

return !$test

score 6 · Answer 1 · answered Sep 20 '13 at 01:30

6

It returns the opposite boolean value of $test. If test is true, or anything that equates to true, it returns false. If it is false, or anything that equates to false, it returns true.

answered Sep 20 '13 at 01:30

John Conde

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[More informations here](http://www.php.net/manual/en/language.types.boolean.php) – Luc M Sep 20 '13 at 01:31
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Let's vote to close this question. – Kermit Sep 20 '13 at 01:32

score 2 · Accepted Answer · answered Sep 20 '13 at 01:42

2

The "!" is the 'NOT' operator.

the "return !$test" check the variable is not true (false). If $test is false then return true.

Ex: !$a >>>> TRUE if $a is not TRUE.

http://www.php.net/manual/en/language.operators.logical.php

answered Sep 20 '13 at 01:42

jonasdiel

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What does the following code do in php?

2 Answers2