How to call a phone number from ios app?

Question

I'm trying to call a phone number from ios app using: It's not working, although the method gets called:

-(IBAction)callPhone:(id)sender {

        NSString *phoneCallNum = [NSString stringWithFormat:@"tel://%@",listingPhoneNumber ];

        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneCallNum]];

        NSLog(@"phone btn touch %@", phoneCallNum);
    }

NSLog output: phone btn touch tel://+39 0668806972

please check this:- http://stackoverflow.com/questions/13306293/whats-the-correct-url-for-placing-a-call-on-an-iphone/13306894#13306894 — Nitin Gohel, Sep 20 '13 at 10:10
also check: http://stackoverflow.com/questions/4582327/how-to-make-a-call-programmatically — Preetam Jadakar, Sep 20 '13 at 10:11
Checkout _Native app URL string_ bullet: https://developer.apple.com/library/ios/featuredarticles/iPhoneURLScheme_Reference/PhoneLinks/PhoneLinks.html#//apple_ref/doc/uid/TP40007899-CH6-SW1 — dvp.petrov, Apr 28 '16 at 14:58

score 89 · Accepted Answer · edited Jul 18 '21 at 08:21

89

your code is correct. did you check in real device. this function will not work in simulator.

try this also,

NSString *phNo = @"+919876543210";
NSURL *phoneUrl = [NSURL URLWithString:[NSString  stringWithFormat:@"telprompt:%@",phNo]];

    if ([[UIApplication sharedApplication] canOpenURL:phoneUrl]) {
        [[UIApplication sharedApplication] openURL:phoneUrl];
    } else
    {
        calert = [[UIAlertView alloc]initWithTitle:@"Alert" message:@"Call facility is not available!!!" delegate:nil cancelButtonTitle:@"ok" otherButtonTitles:nil, nil];
        [calert show];
    }

** Swift 3 version**

if let url = URL(string: "telprompt:\(phoneNumber)") {
  if UIApplication.shared.canOpenURL(url) {
    UIApplication.shared.open(call, options: []) { result in
       // do something with result
    }
  }
}

edited Jul 18 '21 at 08:21

Sandeep Rana

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answered Sep 20 '13 at 10:18

Yas

1,064
9
13

thanks! I tried with the phone number you provided and it works. perhaps it's my phone number formatting. With mine I get "Call facility is not available!!!" could my number be off because of the + as in: +39 0668806972 – user2588945 Sep 20 '13 at 10:31
3

my problem was the whitespace that I stripped out. then it worked. thanks! – user2588945 Sep 20 '13 at 11:01
`telprompt:` is not official and it may be both removed in future versions or your app may be rejected. – Nat Apr 03 '15 at 10:37
4

Hey you are missing // after telprompt:-----Should be telprompt:// . -1 for being careless. Took quite sometime for me to find the problem. :P – Prajeet Shrestha May 11 '15 at 01:23

score 14 · Answer 2 · edited Jan 21 '16 at 12:42

Telephony does not work on simulators/iPod/iPad, you will require to run the app on an iPhone with active sim card.

Also the URL scheme to invoke the telephony application is tel:<phone_number>. Refer Apple docs.

Ideally, you should check if the device is having the telephony module and then perform the openURL: call. Use this code to perform the check,

if([[UIApplication sharedApplication] canOpenURL:callUrl]) {
    [[UIApplication sharedApplication] openURL:callUrl];
}
else {
    //Show error message to user, etc.
}

score 5 · Answer 3 · answered Sep 20 '13 at 10:14

5

Use following method to make call:

 NSString *phoneNumber = [@"tel://" stringByAppendingString:number];
 [[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];

answered Sep 20 '13 at 10:14

Divya Bhaloidiya

5,018
2
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1

Be aware that the `telprompt:` is not a official scheme and can therefor be removed from iOS in future versions. – rckoenes Sep 20 '13 at 10:15

score 0 · Answer 4 · answered Sep 20 '13 at 10:12

0

You can try like below.

NSString *phoneNumber = [@"tel://" stringByAppendingString:Number];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];

Hope it helps you.

answered Sep 20 '13 at 10:12

Manthan

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Remove the `//` from `tel:` they are not in the [tel URL scheme](https://developer.apple.com/library/ios/featuredarticles/iPhoneURLScheme_Reference/Articles/PhoneLinks.html#//apple_ref/doc/uid/TP40007893-SW1) – rckoenes Sep 20 '13 at 10:14
I tried this and nothing happens. the method gets called along with the nslog output: phone btn touch tel:+39 0668806972 – user2588945 Sep 20 '13 at 10:24
Are you testing on an iphone? caz this is the right code man. – Manthan Sep 20 '13 at 10:26
@Manthan yes, testing on a device. I wonder if it's the format of my phone number. I tried +919876543210 and it works but then with +39 0668806972 it doesn't – user2588945 Sep 20 '13 at 10:41
1

Hmm so check out the formant its not correct then. – Manthan Sep 20 '13 at 10:43
@Manthan remove the space perhaps? – user2588945 Sep 20 '13 at 10:43
try it may be thats what causing the problem for you. – Manthan Sep 20 '13 at 10:44
my problem was the whitespace that I stripped out. then it worked. thanks! – user2588945 Sep 20 '13 at 11:01
Ohkk. then please and upvote it if my answer helped you. – Manthan Sep 20 '13 at 11:10

score 0 · Answer 5 · answered Sep 20 '13 at 10:17

0

 NSString *phoneNumber = [@"tel://" stringByAppendingString:@"9414481799"];
 [[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];

This will only run on device.

answered Sep 20 '13 at 10:17

kshitij godara

1,523
18
30

How to call a phone number from ios app?

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