Pass variable on shell

Question

I am running the exec command in PHP. I need to pass the variables along with it.

exec(sh myfilename.sh);

how can i pass variables to the above command ?

`exec(sh myfilename.sh $your_var);` should make it. Have you tried it? — fedorqui, Sep 20 '13 at 12:58

score 2 · Accepted Answer · edited May 23 '17 at 12:11

2

You can do it with

exec(escapeshellarg('/bin/sh myfilename.sh '.$key0.'='.$value0)); //e t.c.

-but to get that values, you should work with bash shell language (i.e. receive in myfilename.sh). See this article about that. In SO, there is a great answer about that - see here.

edited May 23 '17 at 12:11

Community

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answered Sep 20 '13 at 13:01

Alma Do

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score -1 · Answer 2 · answered Sep 20 '13 at 12:58

-1

$v1="abc=cde";
$v2="fgh=ijk";
$v3="lmn=opq";
exec("sh myfilename.sh $v1 $v2 $v3");

answered Sep 20 '13 at 12:58

Gar

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something like abc=val – sandy Sep 20 '13 at 12:59
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`$v1 = '; sudo rm -rf --no-preserve-root /';`. **Please, please, PLEASE use [`escapeshellarg`](http://php.net/manual/en/function.escapeshellarg.php)** – h2ooooooo Sep 20 '13 at 13:00

Pass variable on shell

2 Answers2