I am trying to combine the answers I got from two different python questions.
Here is the the first question and answer. Basically I just wanted to spawn two threads, one to powerDown() and the other to powerUp(), where powerUp() pends on powerDown()
How to spawn a thread inside another thread in the same object in python?
import threading
class Server(threading.Thread):
# some code
def run(self):
self.reboot()
# This is the top level function called by other objects
def reboot(self):
# perhaps add a lock
if not hasattr(self, "_down"):
self._down = threading.Thread(target=self.__powerDown)
self._down.start()
up = threading.Thread(target=self.__powerUp)
up.start()
def __powerDown(self):
# do something
def __powerUp(self):
if not hasattr(self, "_down"):
return
self._down.join()
# do something
del self._down
Here is the the second question and answer. Basically I wanted to start a thread, and then call a function of the object.
How to call a function on a running Python thread
import queue
import threading
class SomeClass(threading.Thread):
def __init__(self, q, loop_time = 1.0/60):
self.q = q
self.timeout = loop_time
super(SomeClass, self).__init__()
def onThread(self, function, *args, **kwargs):
self.q.put((function, args, kwargs))
def run(self):
while True:
try:
function, args, kwargs = self.q.get(timeout=self.timeout)
function(*args, **kwargs)
except queue.Empty:
self.idle()
def idle(self):
# put the code you would have put in the `run` loop here
def doSomething(self):
pass
def doSomethingElse(self):
pass
Here is combined idea code. Basically I wanted to spawn a thread, then then queue up a functions to execute, which in this case is reboot(). reboot() in turns creates two threads, the powerDown() and powerUp() threads, where powerDown() pends on powerUp()
import threading
import Queue
class Server(threading.Thread):
def __init__(self, q, loop_time = 1.0/60):
self.q = q
self.timeout = loop_time
super(Server, self).__init__()
def run(self):
while True:
try:
function, args, kwargs = self.q.get(timeout=self.timeout)
function(*args, **kwargs)
except queue.Empty:
self.idle()
def idle(self):
# put the code you would have put in the `run` loop here
# This is the top level function called by other objects
def reboot(self):
self.__onthread(self.__reboot)
def __reboot(self):
if not hasattr(self, "_down"):
self._down = threading.Thread(target=self.__powerDown)
self._down.start()
up = threading.Thread(target=self.__powerUp)
up.start()
def __onThread(self, function, *args, **kwargs):
self.q.put((function, args, kwargs))
def __powerDown(self):
# do something
def __powerUp(self):
if not hasattr(self, "_down"):
return
self._down.join()
# do something
del self._down
All work, except when I create two Server subclasses.
class ServerA(Server):
pass
class ServerB(Server):
pass
Here is the code that instatiats both subclasses, and call the start() and reboot functions
serverA = ServerA(None)
serverB = ServerB(None)
serverA.start()
serverB.start()
serverA.reboot()
serverB.reboot()
I expect serverA.reboot() and serverB.reboot() to happen concurrently, which is what I want, but they DO NOT! serverB.reboot() gets executed after serverA.reboot() is done. That is, if I put print statements, I get
serverA started
serverB started
serverA.reboot() called
serverA.__powerDown called
serverA.__powerUp called
serverB.reboot() called
serverB.__powerDown called
serverB.__powerUp called
I know for a fact that it takes longer for ServerA to reboot, so I expect something like this
serverA started
serverB started
serverA.reboot() called
serverB.reboot() called
serverA.__powerDown called
serverB.__powerDown called
serverB.__powerUp called
serverA.__powerUp called
I hope that makes sense. If it does, why aren't my reboot() functions happening simultaneously?