You are very close. You should assign the Foo.prototype
to the origFoo.prototype
in order to get the same prototype chain. Everything else is spot on!
Example:
var Foo = function () {
console.log('OriginalFoo');
};
Foo.prototype.method1 = function () {
console.log('Method1');
};
OriginalFoo = Foo;
Foo = function () {
OriginalFoo.apply(this, arguments);
console.log('NewFoo');
};
Foo.prototype = OriginalFoo.prototype;
Foo.prototype.method2 = function () {
console.log('Method2');
};
var x = new Foo();
x.method1();
x.method2();
Demo: http://jsbin.com/ibatah/1/edit?js,console,output
PS: There still is the problem of static-like properties (Foo.prop), but i'm afraid i don't have a solution for that other than copying them one at a time.
EDIT: Solution for special constructors.
Indeed there are constructors which don't like to be called as functions ex: Image
. To get over it, you can do the more awkard solution below. You take advantage of the fact that you can return an object from the constructor and it takes the place of the one created with new. In the overridden constructor you must always use this new object when calling methods instead of this
.
var Foo = function(a,b,c) {
console.log('OriginalFoo',a,b,c);
};
Foo.prototype.prop1 = 'Property1';
Foo.prototype.method1 = function() {
console.log('Method1', this.prop1);
};
OriginalFoo = Foo;
Foo = function(a,b,c) {
var obj = new OriginalFoo(a,b,c);
obj.init('Changed...'); // or this.init.call(obj,'Changed!');
this.init('Not Changed'); // applies to a discarded object, has no effect
console.log('NewFoo');
return obj;
};
Foo.prototype = OriginalFoo.prototype;
Foo.prototype.prop2 = 'Property2';
Foo.prototype.method2 = function() {
console.log('Method2', this.prop2);
};
Foo.prototype.init = function(param) {
this.prop2 = param;
};
var x = new Foo('1','2','3');
console.log(x.prop1);
console.log(x.prop2);
x.method1();
x.method2();
Demo: http://jsbin.com/ibatah/2/edit?js,console,output