IMPORTANCE OF LOGICAL NOT IN PHP

Question

Is it same in PHP:

if($x!=5)
{
 //code
}

VS

$x=5;
if(!$x)
{
 //code
}

What about if($x)? Expression in IF statement evaluates to either TRUE or FALSE unlike C where it is either 0 or anything other than 0 (say 1 or more). We can test the expression by using var_dump(!$x) in PHP. So,what about if($x)?

http://stackoverflow.com/questions/2382490/how-does-true-false-work-in-php — Emilio Gort, Sep 30 '13 at 04:17

Sobin Augustine · Answer 1 · 2013-09-30T04:30:54.230

0

No,it is not same in PHP:

Logical Operator.

! $x Not TRUE if $x is not TRUE.

Comparison Operators

$x!=5  Not equal  TRUE if $x is not equal to 5

Source: PHP Documentation.

edited Sep 30 '13 at 04:30

answered Sep 30 '13 at 04:21

Sobin Augustine

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You don't need to complicate something that easy! – undone Sep 30 '13 at 04:24
Then blame the PHP documentation. – Sobin Augustine Sep 30 '13 at 04:25
@SobinAugustine yeah,I understand that,but what I mean to say that they can be used in same context,although they are different..right? thanks anyway – Parveez Ahmed Sep 30 '13 at 07:10

score 0 · Answer 2 · answered Sep 30 '13 at 04:30

They are not the same.

The first block of code tests whether or not the variable x does not equal 5.

The 2nd block of code tests whether x is not true. Since you declared a value for $x, the statement will be evaluated as false and the content inside the brackets will not execute.

IMPORTANCE OF LOGICAL NOT IN PHP

2 Answers2