Creating a color array with distinct colors

Question

I'm trying to create an array which includes separate distinct colors. Color array will created automatically when the range 'n' given. It's something as following:

variable n = 2;
colourarrray = [red,green];

variable n = 4;
colourarrray = [red,green,blue,yellow];

What is the easiest method to generate such a color array?

You might create a color spectrum using a `LinearGradientPaint` as seen in [this answer](http://stackoverflow.com/a/6996263/418556). Then you could get the relevant color using a loop and incrementing the `x` value used to get the corresponding color in the gradient. — Andrew Thompson, Oct 02 '13 at 14:19

score 0 · Answer 1 · answered Oct 02 '13 at 14:21

An enum. Because it is scalable.

public enum Colors 
{
    BLACK(255, 255, 255),
    WHITE(0, 0, 0);

    private int red;  
    private int green;
    private int blue;

    private Colors(final int red, final int green, final int blue)
    {
        this.red = red;
        this.green = green;
        this.blue = blue;
    }

    public int red()
    {
        return red;
    }

    public int green()
    {
        return green;
    }

    public int blue()
    {
        return blue;
    }
}

Then dinamically add them to a List<Colors> as you need them.

score 0 · Answer 2 · answered Oct 02 '13 at 14:30

Since you didn't put any specification, additional infos or anything to your question and I have nothing better to do right now:

private java.util.Random rnd = new java.util.Random();

public java.awt.Color[] getColors(int num) {
    java.util.List<java.awt.Color> colors = new java.util.ArrayList<>(num);
    int i = 0;
    while (i++ < num) {
        colors.add(new java.awt.Color(rnd.nextInt(255), rnd.nextInt(255), rnd.nextInt(255), 100));
    }
    java.awt.Color[] array = colors.toArray(new java.awt.Color[num]);
    return array;
}

Creating a color array with distinct colors

2 Answers2