I have:
data = [[u'text'],[u'element'],[u'text00']]
pattern = text
pattern2 = EL
pattern3 = 00
Using regex I want to search and return:
text, text00 # for pattern
element # for pattern2
text00 # for pattern3
Asked
Active
Viewed 3,447 times
0
-
What are you expecting? – TerryA Oct 03 '13 at 03:25
-
To find the pattern. If user enters "red" and the list is ["red", "lightred", "orange red", "blue"] then it should return true. – Oct 03 '13 at 03:37
-
That's what `if pattern in data:` already returns – TerryA Oct 03 '13 at 03:38
-
@Haidro I think OP wants "red", "lightred", "orange red" to be returned for `red`. – Santosh Kumar Oct 03 '13 at 03:39
-
@SantoshKumar hm, thought so. Just odd how the example structure already has `red` in it – TerryA Oct 03 '13 at 03:40
-
It doesn't work if the pattern is not exactly the same as entered. So if I enter "tred" even though it is in "lightred" it will return false. – Oct 03 '13 at 03:40
2 Answers
2
I think what you're looking for is any():
>>> L = ["red", "lightred", "orange red", "blue"]
>>> keyword = 'red'
>>> import re
>>> any(re.search(keyword, i) is not None for i in L)
True
TerryA
- 58,805
- 11
- 114
- 143
-
OK, this is useful butI get: TypeError: expected string or buffer. Please note that L will be a list like this: [[[u'red']], [u'blue'], [[u'lightred']]] and keyword is user input – Oct 03 '13 at 03:50
-
@rebHelium That's a very odd list. Using the code [here](http://stackoverflow.com/questions/2158395/flatten-an-irregular-list-of-lists-in-python/2158532#2158532), flatten the list, then use my code – TerryA Oct 03 '13 at 04:01
2
import re
data = [[u'text'], [u'element'], [u'text00']]
patterns = [u'text', u'EL', u'00']
results = []
for pattern in patterns:
results.append([x[0] for x in data if re.search(pattern, x[0], flags=re.I)])
print results
or, more concisely:
import re
data = [[u'text'], [u'element'], [u'text00']]
patterns = [u'text', u'EL', u'00']
results = [[x[0] for x in data if re.search(pattern, x[0], flags=re.I)] for pattern in patterns]
print results
Josha Inglis
- 1,018
- 11
- 23