A function for user defined array

Question

Hi this is program I created for making a user defined array.

This is only a small part of my project and I would like to make it into a static function named 'input(n)',where n is the size of the array.

int main() {


    int* a=0;
    int n,x;
    std::cout<<"Enter size ";
    std:: cin>>n;
    std::cout<<"Enter elements ";
    a=new int(n);

    for(int i=0;i<n;i++){
    std::cin>>x;
    a[i]=x;
    }


for(int j=0;j<n;j++ ){std::cout<<a[j];}
getch();         

}

Any hints on how to get it started?

Remark: `new int(n)` doesn't allocate memory for n ints, `new int[n]` does (even better, scrap `int*` and use `std::vector`. — Zeta, Oct 05 '13 at 08:10
Possible duplicate of [How do I declare an array without initializing a constant?](https://stackoverflow.com/questions/49596685/how-do-i-declare-an-array-without-initializing-a-constant) — Omar Sherif, Apr 27 '19 at 19:40

score 1 · Answer 1 · answered Oct 05 '13 at 08:10

1

int * input(size_t n)
{
    int *p =new int[n];
    int x;
    for(size_t i=0;i<n;i++)
    {
      std::cin>>x;
      p[i]=x;
    }

    return p;
}

Then,

a=input(n);

Don't forget to free memory.

answered Oct 05 '13 at 08:10

P0W

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Arpit · Accepted Answer · 2013-10-05T08:29:36.800

1

#include <iostream>
using namespace std;

static int* getInput(int n){
    int* a=0;
    int x;
    a=new int[n];
    for(int i=0;i<n;i++){
    cin>>x;
    a[i]=x;
    }
    return a;
    }

int main() {
    int *a;
    int n=5;
    a=getInput(n);
    for(int j=0;j<n;j++ )
    {
        cout<<a[j];
    }
    delete[] a;
}

DEMO

edited Oct 05 '13 at 08:29

answered Oct 05 '13 at 08:19

Arpit

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A function for user defined array

2 Answers2