Taking the argument by && in std::vector push_back() and std::map operator[]

Question

I found this in std::vector::push_back() implementation:

void push_back(_Ty&& _Val)
{
    // some code here       
}

and this in std::map operator[] implementation:

mapped_type& operator[](key_type&& _Keyval)
{
    // some code here   
}

Why _Val and _Keyval is taking by the reference-by-reference? How does the taking of the argument by reference-by-reference working? What are the benefits of this approach in comparison with the taking by reference?

P.S. This is NOT the logical "AND", I understand this clearly.

read manual: http://en.cppreference.com/w/cpp/container/vector/push_back — billz, Oct 05 '13 at 12:21
I think this reference may the right to exist, although it's a duplicate. — Netherwire, Oct 06 '13 at 17:14

score 2 · Accepted Answer · answered Oct 05 '13 at 12:21

2

This is a C++11 feature - rvalue references... Here's some more info

answered Oct 05 '13 at 12:21

Tom

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Taking the argument by && in std::vector push_back() and std::map operator[]

1 Answers1