acess element of NSArray with its index

Question

Is it possible to access elements of an NSArray based on index and use them for comparison/operations?

Just like arrayName[ith element] in C/C++

also have you tried reading the documentation of `NSArray` before asking a basic question like this? — Gabriele Petronella, Oct 07 '13 at 05:07

score 13 · Accepted Answer · edited Oct 07 '13 at 13:37

13

Yes , you can access elements of an NSArray based on index .

NSArray *a=@[@"s1",@"s2",@"s3"];
NSLog(@"%@",a[1]);

edited Oct 07 '13 at 13:37

answered Oct 07 '13 at 05:02

Toseef Khilji

score 7 · Answer 2 · edited Mar 01 '17 at 07:51

7

Try this

arrayName[yourIndex];

or

[arrayName objectAtIndex:yourIndex];

edited Mar 01 '17 at 07:51

Nathan

answered Oct 07 '13 at 05:01

Jay Gajjar

score 0 · Answer 3 · answered Oct 07 '13 at 05:00

0

Try this way.

[arrayname objectAtindex:yourIndex]

answered Oct 07 '13 at 05:00

user1673099

score 0 · Answer 4 · answered Oct 07 '13 at 05:04

0

You can use 'Index Subscripting Literal' that Apple Provide on iOS 6 SDK later

NSArray *array = @[1, 2, 3];
NSLog(@"%@", array[0])

answered Oct 07 '13 at 05:04

subscripting has nothing to do with the SDK. It's a compiler feature. – Gabriele Petronella Oct 07 '13 at 05:05
1

@GabrielePetronella That is half true. The syntax itself comes from the compiler, but the actual functions that implement it are part of the iOS 6 SDK (You only have to build with it, it will use some magic to insert itself into older versions at runtime) – borrrden Oct 07 '13 at 05:47
@borrden, fair enough. I guess it's a matter of wording. Subscripting literals are a compiler feature, but Apple indeed started taking advantage on them from iOS 6 on. – Gabriele Petronella Oct 07 '13 at 13:36

4 Answers4